HELP ME PLEASSEEEE use each numbers 2,3,7,8 and use operations make the the numbers FROM 20 TO 50 FOR EXAMPLE 2+3+7+8=20

Someone please explain how to do this problem? :) Factor completely 2c5 + 44c4 + 242c3.

frez [133]

2c5+44c4+242c32c5+44c4+242c3=2c3(c+11)(c+11)

8 0

3 years ago

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Solve the equation.

aksik [14]

Answer:

x = -1

Step-by-step explanation:

$\frac{2}{3} - 4x + \frac{7}{2} = -9x + \frac{5}{6}$

Add 4x to each side of the equation

$\frac{2}{3} - 4x + \frac{7}{2} + 4x = -9x + \frac{5}{6} + 4x$

$\frac{2}{3} + \frac{7}{2} = -9x + \frac{5}{6} + 4x$

Subtract ⅚ from each side

$\frac{2}{3} + \frac{7}{2} - \frac{5}{6} = -9x + \frac{5}{6} + 4x - \frac{5}{6}$

$\frac{2}{3} + \frac{7}{2} - \frac{5}{6} = -9x + 4x$

$\frac{4 + 21 + 5}{6} = -5x$

$\frac{30}{6} = -5x$

$5 = -5x$

Divide both sides by -5

$\frac{5}{-5} = \frac{-5x}{-5}$

$-1 = x$

$x = -1$

8 0

3 years ago

Choose the largest fraction.

Rufina [12.5K]

Answer:

9/10

Step-by-step explaation:

8 0

3 years ago

A recent study suggested that 70% of all eligible voters will vote in the next presidential election. Suppose 20 eligible voters

natita [175]

Answer:

0.0479 = 4.79% probability that fewer than 11 of them will vote

Step-by-step explanation:

For each voter, there are only two possible outcomes. Either they will vote, or they will not. The probability of a voter voting is independent of any other voter, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

70% of all eligible voters will vote in the next presidential election.

This means that $p = 0.7$

20 eligible voters were randomly selected from the population of all eligible voters.

This means that $n = 20$

What is the probability that fewer than 11 of them will vote?

This is:

$P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{20,10}.(0.7)^{10}.(0.3)^{10} = 0.0308$

$P(X = 9) = C_{20,9}.(0.7)^{9}.(0.3)^{11} = 0.0120$

$P(X = 8) = C_{20,8}.(0.7)^{8}.(0.3)^{12} = 0.0039$

$P(X = 7) = C_{20,7}.(0.7)^{7}.(0.3)^{13} = 0.0010$

$P(X = 6) = C_{20,10}.(0.7)^{6}.(0.3)^{12} = 0.0002$

$P(X = 5) = C_{20,5}.(0.7)^{5}.(0.3)^{15} \approx 0$

The probability of 5 or less voting is very close to 0, so they will not affect the outcome. Then

$P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0) = 0.0308 + 0.0120 + 0.0039 + 0.0010 + 0.0002 = 0.0479$

0.0479 = 4.79% probability that fewer than 11 of them will vote

8 0

3 years ago

Which pairs of faces will be opposite one another when the prism is created? Check all that apply.

blondinia [14]

A&C
B&F
Try it by fold the prism with paper

7 0

3 years ago

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