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Arlecino [84]
3 years ago
10

Mercury:3.3022 x 10^23 Venus:4.8685 x 10^24 Earth: 5.9722 x 10^23 Mars: 6.4185 x 10^23

Mathematics
2 answers:
n200080 [17]3 years ago
7 0

Answer:

20.5614 × 10^{93}

Step-by-step explanation:

lora16 [44]3 years ago
3 0

Answer:

1.08421 x 10^25 Kg

Step-by-step explanation:

The combined weight of these two bodies would be the addition of the masses of the two bodies.

Given that Earth weight is 5.9736 x 10^24 Kg and Venus is 4.8685 x 10^24 Kg,

The combined weight of Earth and Venus

= 5.9736 x 10^24 Kg + 4.8685 x 10^24 Kg

=10^24(5.9736 + 4.8685)

= 10.8421  × 10^24 Kg

In standard form,

= 1.08421  × 10^25 Kg

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What are the x and y- intercepts for the line 4(y+3)=−2(x+6)?<br><br> Please give an actual answer.
kow [346]
Hello!

X and Y intercepts are found when graphing an equation. You know the X and Y intercepts by when a point crosses the X axis, and for the Y intercept, when a point crosses the Y axis.

First off we must simplify the equation.

4y + 12 = -2x - 12

Here is the photo of the graph attached.

By looking at the graph we can see the answer is...

X intercept = (-12,0)
Y intercept = (0,-6)

6 0
4 years ago
A car is approaching a building. When it is 300 ft away, the angle of depression from the top of the building to the car is 42°.
labwork [276]

Answer: 333.2ft

Step-by-step explanation:

We can draw a triangle rectangle, where the distance between the base of the building and the car is one cathetus (300ft)

The height of the building is the other cathetus.

Now, we know that the angle of depression from the top of the building to the car is 42°

This angle is measured from a perpendicular line in from the building, so the "top angle" of the triangle rectangle will be:

90° - 42° = 48°

if we steep on this angle, the 300ft cathetus is the opposite cathetus and the height of the building is the adjacent cathetus.

Here we can use the relation:

Tan(A) = Opposite cathetus/adjacent cathetus:

Then:

Tan(48°) = H/300ft

Tan(48°)*300ft = H = 333.2ft

7 0
4 years ago
Read 2 more answers
A book has 240 pages in it.You read 72 pages. What percentage of the book have you read?
Slav-nsk [51]

Answer:      30

Step-by-step explanation:

72 / 240= .3 x 100=30

7 0
3 years ago
Whats the equation for the slopes (-3,12) (5,2)
bazaltina [42]
m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{2 - 12}{5 - (-3)} = \frac{-10}{5 + 3} = \frac{-10}{8} = -1\frac{1}{4}

y - y₁ = m(x - x₁)
y - 2 = -1¹/₄(x - 5)
y - 2 = -1¹/₄(x) + 1¹/₄(5)
y - 2 = -1¹/₄x + 6¹/₄
  + 2             + 2
     y = -1¹/₄x + 8¹/₄
7 0
3 years ago
The centre of a triangle must always be found inside the triangle. Illustrate the statement with examples or deny the statement
Alla [95]

The center of a triangle must always be found inside the triangle given that it is concurrent point of the three median lines of the triangle all three of which are located only inside of the triangle

The examples of the properties of the center of a triangle are;

  1. The center of the triangle is the centroid of the triangle which is the point of concurrency of the three medians of the triangle, where a median line is the line which connects a vertex to the midpoint of the side opposite the vertex inside the triangle
  2. Each median line divides the area of the triangle in half, and given that the area of the triangle is equal to half the altitude, multiplied by the length of the base side of the triangle, the three medians of a triangle are related and share a common concurrent point <em>inside</em> the triangle such the perpendicular distance from the concurrent point of the three medians to each of the three side is less than the altitude of the triangle

Given that the three medians are located inside the triangle therefore, based on the location of the center of the triangle on the medians of the triangle, the center of the triangle must always be found inside the triangle

Learn more about the centroid of a triangle here;

brainly.com/question/16482898

3 0
3 years ago
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