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Vilka [71]
3 years ago
9

Mr. Taylor's 4th grade class uses Skittles to learn about probability. They open several randomly selected bags of Skittles and

sort and count the different colors and want to determine if Skittles are evenly distributed by color.
Col1 Color Red Orange Yellow Purple Green
Col2 Count 107 101 87 115 10

A) Choose the appropriate null and alternate hypotheses.B)What is the p-value?C)What is your conclusion?
Mathematics
1 answer:
kap26 [50]3 years ago
3 0

Answer:

The skitties are not evenly distributed by colour

Step-by-step explanation:

Given that Mr. T  aylor's 4th grade class uses Skittles to learn about probability. They open several randomly selected bags of Skittles and sort and count the different colors and want to determine if Skittles are evenly distributed by color.

H_0: Skitties are equally distributed\\H_a: atleast two are not equally distributed

(Two tailed chi square test)

If all are equally distributed then expected values would be equal to 420/5 =104

Observed                       Red   Orange  Yellow   Purple   Green  Total

                                       107          101      87           115           10     420

Expected                         104          104     104          104         104    420

Chi square 0.0865 0.0865 2.7788 1.16345 84.9615 89.0769

Chi square is calculated as (obs-exp)^2/exp

Total chi square = 89.0769

df = 4

p value = <0.00001

Reject null hypothesis

The skitties are not evenly distributed by colour

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Temka [501]

Answer:

a) P (x) = (x + 3) (x-1) (x-4)

b) P (x) = (2x + 5) (5x - 4) (x-6)

c) P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2

Step-by-step explanation:

<u>For the question a *</u> you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.

This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.

Then write the polynomial in factored form.

P (x) = (x + 3) (x-1) (x-4)

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.

<u>For question b, do the same procedure</u>.

Degree: 3

Zeros: -5/2, 4/5, 6.

The factors are

x = -\frac{5}{2}\\\\x +\frac{5}{2} = 0\\\\(2x +5) = 0

---------------------------------------

x =\frac{4}{5}\\\\x-\frac{4}{5} = 0\\\\(5x-4) = 0

--------------------------------------

x = 6\\\\(x-6) = 0

--------------------------------------

P (x) = (2x + 5) (5x - 4) (x-6)

<u>Finally for the question c we have</u>

Degree: 5

Zeros: -3, 1, 4, -1

Multiplicity 2 in -1

x = -3\\\\(x-3) = 0

--------------------------------------

x = 1\\\\(x-1) = 0

--------------------------------------

x = 4\\\\(x-4) = 0

----------------------------------------

x = -1\\\\(x + 1) = 0

-----------------------------------------

P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2

8 0
3 years ago
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Answer:

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Step-by-step explanation:

Solve the system of inequalities:

x + 4 < 0

OR:

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x < -4

The second inequality gives the solution:

x > -2

The total solution is the disjunction of the individual solutions, i.e., the union of both.

It can be expressed as

\mathbf{x\in (-\infty , -4) \cup (-2,+\infty)}

4 0
2 years ago
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Answer:

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Step-by-step explanation:

i hope it will help you

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