Answer: Option 'D' is correct.
Step-by-step explanation:
Since we have given that
Mean = 73
Standard deviation = 7.8
Number of students are randomly selected = 24
So, n = 24.
Since it is normally distributed , so, we have
[tex]P(x<70)=P(z<\frac{X-\mu}{\frac{\sigma}{\sqrt{n}}})=P(z<\frac{70-73}{\frac{7.8}{\sqrt{24}}}\\\\P(z<\frac{-3}{1.592})\\\\=P(z<-1.88)\\\\=0.03005=0.0301/tex]
Hence, Option 'D' is correct.
