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3 years ago

14

It is less than 300. The ones digit is four times the hundreds digit. The tens digit is five more than the hundreds digit. The s

um of the digits is 17.

1 answer:

tester [92]3 years ago

3 0

Answer:

Step-by-step explanation:

let the numbers at unit,ten and hundred place be x,y,z respectively,then number=100z+10y+x

also x=4z

y=z+5

and x+y+z=17

4z+z+5+z=17

6z=17-5=12

z=2

y=2+5=7

x=2×4=8

number=100×2+10×7+8=278

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Answer:

the markup is 1016%

Step-by-step explanation:

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3 years ago

I need helpppp (10 points )

irga5000 [103]

Answer: The flagpole is about 22.3 feet tall.

This is roughly the size of a two story building, assuming each floor is 10 feet or so.

Since this height is under 25 ft, this flagpole is in compliance with the regulation.

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Work Shown:

The horizontal leg of the triangle is 36 ft. This is the adjacent leg to the reference angle 25 degrees.

The vertical leg of the triangle is x-5.5, and this leg is the opposite side to the reference angle 25 degrees.

Use the tangent rule to connect the opposite and adjacent sides.

Solve for x.

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Make sure your calculator is in degree mode.

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3 years ago

Two types of defects are observed in the production of integrated circuit boards. It is estimated that 6% of the boards have sol

aalyn [17]

Answer:

(a) 0.09

(b) 0.06

(c) 0.0018

(d) 0.9118

(e) 0.03

Step-by-step explanation:

Let <em>A</em> = boards have solder defects and <em>B</em> = boards have surface defects.

The proportion of boards having solder defects is, P (A) = 0.06.

The proportion of boards having surface-finish defects is, P (B) = 0.03.

It is provided that the events A and B are independent, i.e.

$P(A\cap B)=P(A)\times P(B)$

(a)

Compute the probability that either a solder defect or a surface-finish defect or both are found as follows:

= P (A or B) + P (A and B)

$=P(A)+P(B)-P(A\cap B)+P(A\cap B)\\=P(A)+P(B)\\=0.06+0.03\\=0.09$

Thus, the probability that either a solder defect or a surface-finish defect or both are found is 0.09.

(b)

The probability that a solder defect is found is 0.06.

(c)

The probability that both defect are found is:

$P(A\cap B)=P(A)\times P(B)\\=0.06\times0.03\\=0.0018$

Thus, the probability that both defect are found is 0.0018.

(d)

The probability that none of the defect is found is:

$P(A^{c}\cup B^{c})=1-P(A\cup B)\\=1-P(A)-P(B)+P(A\cap B)\\=1-P(A)-P(B)+[P(A)\times P(B)]\\=1-0.06-0.03+(0.06\times0.03)\\=0.9118$

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(e)

The probability that the defect found is a surface finish is 0.03.

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3 years ago

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3 years ago

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