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3 years ago

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It is less than 300. The ones digit is four times the hundreds digit. The tens digit is five more than the hundreds digit. The s

um of the digits is 17.

1 answer:

tester [92]3 years ago

3 0

Answer:

Step-by-step explanation:

let the numbers at unit,ten and hundred place be x,y,z respectively,then number=100z+10y+x

also x=4z

y=z+5

and x+y+z=17

4z+z+5+z=17

6z=17-5=12

z=2

y=2+5=7

x=2×4=8

number=100×2+10×7+8=278

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A line passes through (2, 8) and (4, 12). Which equation best represents the line? y = 1 over 2 x 6 y = 2x 7 y = 2x 4 y = 1 over

nalin [4]

Equation of the line is a way to represent the a line in a equation or algebraic from which is the set of the line thorough witch the line passes.

Given information-

The point through which the line passes are (2, 8) and (4, 12).

To find the equation of the line, the standard form of the equation of the line must be obtained.

<h3>Equation of the line</h3>

Equation of the line is a way to represent the a line in a equation or algebraic from which is the set of the line thorough witch the line passes.

The standard form of the equation of the line can be given as,

$(y-y_1)=\dfrac{y_2-y_1}{x_2-x_1} (x-x_1)$

Where $(x_1,y_1)$ and $(x_2,y_2)$ are the points through which the line passes.

Thus the equation of the line which passes through the points (2, 8) and (4, 12) can be given as,

$(y-8) &=\dfrac{12-8}{4-2} (x-2)\\(y-8) &=\dfrac{4}{2} (x-2)\\2y-16 &=4x-8\\2y &=4x-8+16\\$

Divide by 2 both the side,

$y=2x-4$

Thus the equation of the line which passes through the points (2, 8) and (4, 12) is,

$y=2x-4$

Hence the option 3 is the correct option.

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3 years ago

What is 100 to the 20th power called?

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I think it is
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ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:

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2.

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400=81+169-234(cosA) 150=-234(cosA)

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3. m(A) = Arccos(-0.641)≈130°,

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2 years ago

B is the midpoint of ac. Ab = x+9 and bc = 3x-7 find x and ac

natali 33 [55]

To solve this problem, we need to know 2 relationships:

<h2>1. AC = AB + BC</h2>

The distance of AC is the sum of AB and BC.

$AC = AB + BC$

We know this since the distance of going from A to C (AC) is the same as going from A to B (AB), then B to C (BC).

<h2>2. AB = BC</h2>

The distance of AB is the same as AC.

$AB = BC$

We know this since B is in the middle of AC, so the distance from B to A (BA) is the same as the distance from B to C (BC).

You can see the attached image (at the bottom) for a visualization of this.

<h2>Putting them together</h2>

Since we know the values of AB and BC...

$AB = x+9\\BC = 3x-7$

...we can put these values into our 2nd equation and solve for x:

$AB = BC\\x + 9 = 3x -7$

Add 7 to both sides:

$x + 16 = 3x$

Subtract x from both sides:

$16 = 2x$

Divide both sides by 2:

$8 = x\\x = 8$

Knowing x, we can find the distance of AC using our first equation.

$AC = AB + BC$

Let's put in the values of AB and BC:

$AC = (x+9) + (3x-7)$

Before we put in x = 8, we can simplify this:

$AC = (x+9) + (3x-7)\\AC = x + 9 + 3x -7\\AC = x + 3x + 9 -7\\AC = 4x + 9 - 7\\AC = 4x+2$

We group x and 3x and add those together. Then we subtract 7 from 9.

With this equation, we can put in x = 8:

$AC = 4x +2\\AC = 4*8 + 2$

Since 4 * 8 = 32:

$AC = 4 * 8 + 2\\AC = 32 + 2\\AC = 34$

Finally, we have found both x and AC.

<h2>Answer</h2>

x = 8

AC = 34

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3 years ago