Answer:
a = 2, b = -9, c = 3
Step-by-step explanation:
Replacing x, y values of the points in the equation y = a*x^2 + b*x +c give the following:
(-1,14)
14 = a*(-1)^2 + b*(-1) + c
(2,-7)
-7 = a*2^2 + b*2 + c
(5, 8)
8 = a*5^2 + b*5 + c
Rearranging:
a - b + c = 14
4*a + 2*b + c = -7
25*a + 5*b + c = 8
This is a linear system of equations with 3 equations and 3 unknows. In matrix notation the system is A*x = b whith:
A =
1 -1 1
4 2 1
25 5 1
x =
a
b
c
b =
14
-7
8
Solving A*x = b gives x = Inv(A)*b, where Inv(A) is the inverse matrix of A. From calculation software (I used Excel) you get:
inv(A) =
0.055555556 -0.111111111 0.055555556
-0.388888889 0.444444444 -0.055555556
0.555555556 0.555555556 -0.111111111
inv(A)*b
2
-9
3
So, a = 2, b = -9, c = 3
Answer:
0.6 or 0.60
Step-by-step explanation:
3/5 mulitply denominator to see how much it goes to 100 which is 20 so 5x20 which is 100 and u go to other number u get 60 so 60/100 or you can just divide 3 by 5 which is also 0.6
Answer: 3, 11
Step-by-step explanation:
Y= 3+8 = 11
X= 11-14=3
One way to solve this problem is by:
First multiply both sides by 10
30r=9
Now divide by 30
r=0.3 Final Answer
namely how many times does ¼ go into 2, well that'd be 2 ÷ ¼,
