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3 years ago

6 divided by 2 (1+2)=

Mathematics

2 answers:

uysha [10]3 years ago

8 0

The answer will be 1

andreyandreev [35.5K]3 years ago

6 0

Answer:

Step-by-step explanation:

6 ÷ 2(1 +2)

6 ÷ (2 + 4)

6 ÷ 6 = 1

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PLEASE HELP

Harrizon [31]

The given triangle is a right triangle

<h3>The length and slope</h3>

The coordinates are given as:

D (0,n), E(m,n), F(m,0)

The length is calculated using:

$l=\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2$

So, we have:

$DE=\sqrt{(0-m)^2 + (n-n)^2} = m$

$DF=\sqrt{(0-m)^2 + (n-0)^2} = \sqrt{m^2 + n^2$

$EF=\sqrt{(m-m)^2 + (n-0)^2} = n$

The slope is calculated using:

$m = \frac{y_2 -y_1}{x_2 - x_1}$

So, we have:

$DE = \frac{n -n}{0- m} = 0$

$DF = \frac{n -0}{0- m} = -\frac nm$

$EF = \frac{n -0}{m- m} = \mathbf{unde fined}$

<h3>The coordinates of the midpoints</h3>

This is calculated using

$m = 0.5 * (x_1 + x_2, y_1 + y_2)$

So, we have:

$DE = 0.5 * (0 + m, n+ n)=(0.5m, n)$

$DF = 0.5 * (0 + m, n+ 0)=(0.5m, 0.5n)$

$EF = 0.5 * (m + m, n+ 0)=(m, 0.5n)$

<h3>The type of triangle</h3>

In (a), we have:

<u>Lengths</u>

$DE= m$

$DF = \sqrt{m^2 + n^2$

$EF= n$

<u>Slope</u>

$DE = 0$

$DF = -\frac nm$

$EF = \mathbf{unde fined}$

The sides are not equal.

However, the 0 and the undefined slope implies that the triangle is a right triangle because the sides are perpendicular

It should be noted that the triangle cannot be graphed because the coordinates are not numeric

Read more about triangles at:

brainly.com/question/26331644

#SPJ1

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