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Mumz [18]
2 years ago
9

A rowing team rowed 90 miles while going with the current in the same amount of time as it took to row 10 miles going against th

e current. The rate of the
current was 4 miles per hour. Find the rate of the rowing team in still water.
Mathematics
1 answer:
SVETLANKA909090 [29]2 years ago
8 0

Answer:

5mph

Step-by-step explanation:

Let speed of boat in still water is s.

Distance proportional to speed

90/10 = (s+ 4)/(s - 4)

=> 9s - 36 = s + 4

=> 8s = 40

=> s= 5 mph

:-)

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Answer:

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Option 3

Step-by-step explanation:

When equations are equivalent, they will have infinitely many solutions.

If you want to find an equivalent equation, you can <u>multiply/divide every</u> term in the equation by the same number. You can also <u>rearrange</u> the equation.

Since the options mostly have "y" by itself, start by <u>rearranging</u> to isolate "y" in the given equation.

Move all the other numbers to the right of the equal sign except for "y". To move a number, apply its reverse operation to the entire equation.

Do reverse operations in reverse BEDMAS order.

2y - 4x = 6                Move "-4x" first. It's reverse is +4x.

2y - 4x + 4x = 6 + 4x

2y = 6 + 4x                Move the "2" in 2y. Divide the whole equation by 2.

2y/2 = 6/2 + 4x/2

y = 3 + 2x                  Rearrange to look like the answer choices.

y = 2x + 3

This equation looks like option 3 except every term has a different negative/positive.

y = 2x + 3         -y = -2x - 3

We can <u>multiply every term</u> by -1.

y = 2x + 3

y*-1 = 2x*-1 + 3*-1

-y = -2x + (-3)                Negative and positive make a negative

-y = -2x - 3                     Same as option 3

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