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ra1l [238]
3 years ago
6

D-I are the measurements of the lengths of the sides of triangles. Identify the types of triangles.

Mathematics
1 answer:
ivann1987 [24]3 years ago
5 0
D. scalene
e. isosceles
f. isosceles
g. equilateral
h. scalene
i. equilateral
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kondor19780726 [428]

Answer:

all work is shown and pictured

7 0
4 years ago
7x-5y<-15 graph and shade
vaieri [72.5K]

Answer:

Slope: 7/5

y intercept: (0,3)

Step-by-step explanation:

8 0
3 years ago
Anyone know this ??
Nady [450]

Answer: The first one does not belong, neither does the third.

Step-by-step explanation:

The second one belongs as 30+5=35. You can divide 35 by 5 to get A=7. This is a valid answer. The third is the same as the first. The fourth acts for 30+25=5. 55/5=11.A=11. This is also a valid answer. So, the first one does not belong and neither does the third.

6 0
3 years ago
Suppose a large labor union wishes to estimate the mean number of hours per month a union member is absent from work. The union
frosja888 [35]

Answer:

The 99% confidence interval for the true mean number of hours a union member is absent per month is (0 hours, 16.5125 hours).

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find M as such

M = z*s

In which s is the standard deviation of the sample.

So

M = 2.575*3.5 = 9.0125

The lower end of the interval is the mean subtracted by M. So it is 7.5 - 9.0125 = -...

There is not a negative number of hours. So the lower end of the interval is 0 hours.

The upper end of the interval is the mean added to M. So it is 7.5 + 9.0125 = 16.5125 hours.

The 99% confidence interval for the true mean number of hours a union member is absent per month is (0 hours, 16.5125 hours).

8 0
4 years ago
Q5: Identify the graph of the equation and write an equation of the translated or rotated graph in general form.
MAVERICK [17]

Answer:

d.\:ellipse;\:3x^2+y^2+6x-6y+3=0.

Step-by-step explanation:

The given conic has equation;

3x^2+y^2=9

Divide through by 9.

\Rightarrow \frac{3x^2}{9}+\frac{y^2}{9}=\frac{9}{9}

\Rightarrow \frac{x^2}{3}+\frac{y^2}{9}=1.

This is an ellipse centered at the origin;

This ellipse has been translated so that the center is now at;

(-1,3)

The translated ellipse has equation;

\frac{(x+1)^2}{3}+\frac{(y-3)^2}{9}=1.

Clear the fraction;

3(x+1)^2+(y-3)^2=9.

Expand;

3(x^2+2x+1)+(y^2-6y+9)=9.

3x^2+6x+3+y^2-6y+9=9.

Write in general form;

3x^2+y^2+6x-6y+9-9+3=0.

3x^2+y^2+6x-6y+3=0.

The correct choice is D

4 0
3 years ago
Read 2 more answers
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