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fiasKO [112]
3 years ago
6

Q5: Identify the graph of the equation and write an equation of the translated or rotated graph in general form.

Mathematics
2 answers:
Gennadij [26K]3 years ago
6 0

Answer:

d.

ellipse;

Step-by-step explanation:

MAVERICK [17]3 years ago
4 0

Answer:

d.\:ellipse;\:3x^2+y^2+6x-6y+3=0.

Step-by-step explanation:

The given conic has equation;

3x^2+y^2=9

Divide through by 9.

\Rightarrow \frac{3x^2}{9}+\frac{y^2}{9}=\frac{9}{9}

\Rightarrow \frac{x^2}{3}+\frac{y^2}{9}=1.

This is an ellipse centered at the origin;

This ellipse has been translated so that the center is now at;

(-1,3)

The translated ellipse has equation;

\frac{(x+1)^2}{3}+\frac{(y-3)^2}{9}=1.

Clear the fraction;

3(x+1)^2+(y-3)^2=9.

Expand;

3(x^2+2x+1)+(y^2-6y+9)=9.

3x^2+6x+3+y^2-6y+9=9.

Write in general form;

3x^2+y^2+6x-6y+9-9+3=0.

3x^2+y^2+6x-6y+3=0.

The correct choice is D

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