write a problem that includes multiplying decimals. explain how you know where to place the decimal in the prouduct

Mathematics

1 answer:

sergij07 [2.7K]2 years ago

3 0

3.6 x 3.4.

6 times 4 is 24 so carry the 2. next 4 times 3 is 12 then add the so 14.

Next you do the left side; 3 times 3 is 9.. then 3 times 6 is equals 18.

Now u should have 144 on top and 189 you add those; which equals 333. In each number (3.6 and 3.4); the decimal moved over once so 1 times 2 = 2

so move the decimal over twice and the answer would be 3.33

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<h2>Hello!</h2>

The answer is:

The ball will hit the ground after $t=2.47s$

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So,

$\frac{-b+-\sqrt{b^{2} -4ac} }{2a}$

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Then, substituting it into the quadratic equation, we have:

$\frac{-b+-\sqrt{b^{2} -4ac} }{2a}=\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}\\\\\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}=\frac{3+-\sqrt{9+760} }{-10}\\\\\frac{3+-\sqrt{9+760} }{-10}=\frac{3+-\sqrt{769} }{-10}=\frac{3+-27.731}{-10}\\\\t1=\frac{3+27.731}{-10}=-3.073s\\\\t2=\frac{3-27.731}{-10}=2.473s$