Please help please help please help please help please help please help
1 answer:
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let each box length be 1
<em><u>for</u></em><em><u> </u></em><em><u>white</u></em><em><u> </u></em><em><u>triangle</u></em>
area = ½bh
=½(4)(2)
=4
<em><u>f</u></em><em><u>o</u></em><em><u>r</u></em><em><u> </u></em><em><u>o</u></em><em><u>r</u></em><em><u>a</u></em><em><u>n</u></em><em><u>g</u></em><em><u>e</u></em><em><u> </u></em><em><u>t</u></em><em><u>r</u></em><em><u>i</u></em><em><u>a</u></em><em><u>n</u></em><em><u>g</u></em><em><u>l</u></em><em><u>e</u></em>
area=½(2)(3)
=3
<em><u>f</u></em><em><u>o</u></em><em><u>r</u></em><em><u> </u></em><em><u>b</u></em><em><u>l</u></em><em><u>u</u></em><em><u>e</u></em><em><u> </u></em><em><u>m</u></em><em><u>a</u></em><em><u>r</u></em><em><u>k</u></em><em><u>e</u></em><em><u>d</u></em><em><u> </u></em><em><u>b</u></em><em><u>o</u></em><em><u>x</u></em><em><u>e</u></em><em><u>s</u></em>
each of the box
area=l²
=(1)²
=1
there are 16 boxes
so the total area will be 16
total area of the hexagon = 4+3+16
=23 square units
Fraction adding: Okay, so if you have two fractions with the same denominator like 2/3 and 1/3 then they are easily added. Just add the numerators together and then keep the denominator. Like this: 2/3 + 1/3 = 3/3 or 1 whole. Here is something for fractions with unlike denominators.
