Answer:
Combine terms with the same variable and the same exponent
Step-by-step explanation:
remember that when you combine like terms, you combine the terms with the exact same variable by adding them or subtracting them, depending on the operation they have attached to them. Terms with exponents work exactly the same way! hope this helps you :)
Most quadratic functions(which is what you have there, to a degree of 2) are solved using factoring and the zero product law. If you can not factor then you have to use the quadratic formula or graph it. However this one can be factored.
It's pretty simple to just factor it by inspection but I use the chart method, if you know decomposition that works as well.
Factoring gives us,

Then you set each factor to 0 and solve for x,



And the second one,


The solutions to this equation are
x = -1/2, 3
Answer:
All real numbers except x cannot equal 10.
Step-by-step explanation: the denominator can not equal to zero that is undefined.
Answer: D
Step-by-step explanation:
in the first equation you need to shade below and for the second equation you need to shade to the right and the only place where the shading matches is in section d
Answer:
<h2><em>
2(3s-14)</em></h2>
Step-by-step explanation:
Given the angles ∠ABF=8s-6, ∠ABE = 2(s + 11), we are to find the angle ∠EBF. The following expression is true for the three angles;
∠ABF = ∠ABE + ∠EBF
Substituting the given angles into the equation to get the unknown;
8s-6 = 2(s + 11)+ ∠EBF
open the parenthesis
8s-6 = 2s + 22+ ∠EBF
∠EBF = 8s-6-2s-22
collect the like terms
∠EBF = 8s-2s-22-6
∠EBF = 6s-28
factor out the common multiple
∠EBF = 2(3s-14)
<em></em>
<em>Hence the measure of angle ∠EBF is 2(3s-14)</em>