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Allisa [31]
3 years ago
7

I need help please .

Mathematics
1 answer:
Vinvika [58]3 years ago
5 0

Answer:

Step-by-step explanation:

Using the quotient rule, you subtract the like terms together.

p^9 - p^3 is equal to p^6

q^5 - q^3 is equal to q^2

Your answer is p^6q^2

You might be interested in
Drag each number to the correct location on the table. Each number can be used more than once, but not all numbers will be used.
muminat

Answer:

1. 12x^2-13.4x-11

- Degree: 2

- Number of terms: 3

2. 7x^3+168

 - Degree: 3

- Number of terms: 2

3. 9x^4-9

- Degree: 4

- Number of terms: 2

Step-by-step explanation:

For this exercise you need to remember the multiplication of signs:

(+)(+)=+\\(-)(-)=+\\(-)(+)=-\\(+)(-)=-

1. Given:

(4x + 2.2)(3x - 5)

Apply the Distributive property:

=12x^2+6.6x-20x-11

Add the like terms:

=12x^2-13.4x-11

You can idenfity that:

- Degree: 2

- Number of terms: 3

2. Given:

(-304 +503 - 12) + (7x^3 - 25 + 6)

Add the like terms:

=187 + 7x^3 - 25 + 6=7x^3+168

You can idenfity that:

- Degree: 3

- Number of terms: 2

3. Given:

(3x^2 - 3)(3x^2 + 3)

Apply Distributive property:

=9x^4-9x^2+9x^2-9

Add the like terms:

=9x^4-9

You can idenfity that:

- Degree: 4

- Number of terms: 2

8 0
3 years ago
Can 3.65909090909 be expressed as a fraction whose denominator is a power of 10? Explain.
GuDViN [60]
\bf 3.659\textit{ can also be written as }\cfrac{3659}{1000}\textit{ therefore }3.6590909\overline{09}\\\\
\textit{can be written as }\cfrac{3659.0909\overline{09}}{1000}

notice above, all we did, was isolate the "recurring part" to the right of the decimal point, so the repeating 09, ended up on the right of it.

now, let's say, "x" is a variable whose value is the recurring part, therefore then

\bf \cfrac{3659.0909\overline{09}}{1000}\qquad \boxed{x=0.0909\overline{09}} \qquad \cfrac{3659+0.0909\overline{09}}{1000}\implies \cfrac{3659+x}{1000}

now, the idea behind the recurring part is that, we then, once we have it all to the right of the dot, we multiply it by some power of 10, so that it moves it "once" to the left of it, well, the recurring part is 09, is two digits, so let's multiply it by 100 then, 

\bf \begin{array}{llllllll}
100x&=&09.0909\overline{09}\\
&&9+0.0909\overline{09}\\
&&9+x
\end{array}\quad \implies 100x=9+x\implies 99x=9
\\\\\\
x=\cfrac{9}{99}\implies \boxed{x=\cfrac{1}{11}}\\\\
-------------------------------\\\\
\cfrac{3659.0909\overline{09}}{1000}\qquad \boxed{x=0.0909\overline{09}} \quad \cfrac{3659+0.0909\overline{09}}{1000}\implies \cfrac{3659+x}{1000}
\\\\\\
\cfrac{3659+\frac{1}{11}}{1000}

and you can check that in your calculator.
8 0
4 years ago
Solve this equation: 4+k=11
Law Incorporation [45]

Answer:

k=7

Step-by-step explanation:

4+k=11

subtract 4 from both sides to isolate k

k= 7

3 0
3 years ago
I need help with this real quick
Leni [432]

Answer:

A

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
How do I find the area
inn [45]
Wasssaa,

Steps:

To find the area of a triangle you multiply the base times the height, in this case the is (19m)
and the height is (11m), after you multipy those numbers you divide by (2)
(19m \times 11m) \div 2
\frac{209  }{2}

Answer:
104.5sq \: m
Hope this helped you
:D
8 0
3 years ago
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