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morpeh [17]
3 years ago
14

On a piece of paper, use a protractor to construct right triangle DEF with DE=4 in. , m∠D=90° , and m∠E=45° . What statement is

true about the triangle?
Mathematics
2 answers:
Ksenya-84 [330]3 years ago
8 0
The right triangle DEF has two equal sides which are DE and DF with length 4 inches. The side EF which is opposite to the angle m∠D=90° has the longest length with measurement equal to 5.66 inches. The longest side is also called as the hypotenuse.
sergejj [24]3 years ago
8 0
Here, One of the angle in Right-triangle is 45, so other would also equal to 45 degrees, in that case, two sides would also be equal & Triangle is known as "Isosceles right triangle"

So, Draw the 90 degree angle, & two perpendicular line of 4 in. then, join their edges and your triangle will be ready

Hope this helps!
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U = {a, b, c, d, e, f, g}<br> A = {a, c, e, g)<br> B = {a, b, c, d]<br> Find A U B'
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Answer:

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5 0
3 years ago
At the start of 2014 lucys house was worth ?200 000. The value of the house increased by 5% every year. Workout the value of her
Galina-37 [17]

Answer:

The value of Lucys house  at the start of 2017 is 231525.

Step-by-step explanation:

It is given that the initial value of Lucys house is 200,000. The  at the start of 2017.

The exponential function is defined as

P=P_0(1+r)^t

Where, P₀ is initial value, r is growth rate, t is time in years.

The value of house is defined by the function

P=200000(1+0.05)^t

Where, t is number of years after 2014.

P=200000(1.05)^t

The difference between 2017 and 2014 is 3 years.

P=200000(1.05)^3=231525

Therefore the value of Lucys house  at the start of 2017 is 231525.

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4 years ago
Which set is the subset of every set
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What are the solutions of x^2-2x+5=0
sweet [91]

The solution of x^{2}-2 x+5=0 are 1 + 2i and 1 – 2i

<u>Solution:</u>

Given, equation is x^{2}-2 x+5=0

We have to find the roots of the given quadratic equation

Now, let us use the quadratic formula

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}  --- (1)

<em><u>Let us determine the nature of roots:</u></em>

Here in x^{2}-2 x+5=0 a = 1 ; b = -2 ; c = 5

b^2 - 4ac = 2^2 - 4(1)(5) = 4 - 20 = -16

Since b^2 - 4ac < 0 , the roots obtained will be complex conjugates.

Now plug in values in eqn 1, we get,

x=\frac{-(-2) \pm \sqrt{(-2)^{2}-4 \times 1 \times 5}}{2 \times 1}

On solving we get,

x=\frac{2 \pm \sqrt{4-20}}{2}

x=\frac{2 \pm \sqrt{-16}}{2}

x=\frac{2 \pm \sqrt{16} \times \sqrt{-1}}{2}

we know that square root of -1 is "i" which is a complex number

\begin{array}{l}{\mathrm{x}=\frac{2 \pm 4 i}{2}} \\\\ {\mathrm{x}=1 \pm 2 i}\end{array}

Hence, the roots of the given quadratic equation are 1 + 2i and 1 – 2i

6 0
3 years ago
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