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scoundrel [369]
3 years ago
7

15 PTS PLEASE HELP IF RIGHT 5 STARS AND A BRAINLIEST IF WRONG 1 STAR Which statement best describes a tangent of a circle?

Mathematics
1 answer:
Ede4ka [16]3 years ago
6 0

b. It is a segment that touches the circle in exactly one point and makes a right angle with the radius.


Nothing really to be explained, it just the definition of the tangent.

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You buy some dining room furniture. The table costs $599.99 and 4 chairs cost $89.59/ chair. How much is your total purchase?
Rashid [163]

Answer: the chairs alone would cost $358.36, and since you would already know how much the table costs you would just add it together to get $958.35


Step-by-step explanation:


3 0
3 years ago
Read 2 more answers
Tom rolls 2 fair dice and adds the results from each. Work out the probability of getting a total that is a factor of 21.
nika2105 [10]

Answer:

3 plus 4. and 2 plus 1. or 4 plus 3 or 1 plus 2

Step-by-step explanation:

5 0
3 years ago
What is the upper bound of the function f(x)=4x4−2x3+x−5?
inessss [21]

Answer:

(no global maxima found)

Step-by-step explanation:

Find and classify the global extrema of the following function:

f(x) = 4 x^4 - 2 x^3 + x - 5

Hint: | Global extrema of f(x) can occur only at the critical points or the endpoints of the domain.

Find the critical points of f(x):

Compute the critical points of 4 x^4 - 2 x^3 + x - 5

Hint: | To find critical points, find where f'(x) is zero or where f'(x) does not exist. First, find the derivative of 4 x^4 - 2 x^3 + x - 5.

To find all critical points, first compute f'(x):

d/( dx)(4 x^4 - 2 x^3 + x - 5) = 16 x^3 - 6 x^2 + 1:

f'(x) = 16 x^3 - 6 x^2 + 1

Hint: | Find where f'(x) is zero by solving 16 x^3 - 6 x^2 + 1 = 0.

Solving 16 x^3 - 6 x^2 + 1 = 0 yields x≈-0.303504:

x = -0.303504

Hint: | Find where f'(x) = 16 x^3 - 6 x^2 + 1 does not exist.

f'(x) exists everywhere:

16 x^3 - 6 x^2 + 1 exists everywhere

Hint: | Collect results.

The only critical point of 4 x^4 - 2 x^3 + x - 5 is at x = -0.303504:

x = -0.303504

Hint: | Determine the endpoints of the domain of f(x).

The domain of 4 x^4 - 2 x^3 + x - 5 is R:

The endpoints of R are x = -∞ and ∞

Hint: | Evaluate f(x) at the critical points and at the endpoints of the domain, taking limits if necessary.

Evaluate 4 x^4 - 2 x^3 + x - 5 at x = -∞, -0.303504 and ∞:

The open endpoints of the domain are marked in gray

x | f(x)

-∞ | ∞

-0.303504 | -5.21365

∞ | ∞

Hint: | Determine the largest and smallest values that f achieves at these points.

The largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:

The open endpoints of the domain are marked in gray

x | f(x) | extrema type

-∞ | ∞ | global max

-0.303504 | -5.21365 | global min

∞ | ∞ | global max

Hint: | Finally, remove the endpoints of the domain where f(x) is not defined.

Remove the points x = -∞ and ∞ from the table

These cannot be global extrema, as the value of f(x) here is never achieved:

x | f(x) | extrema type

-0.303504 | -5.21365 | global min

Hint: | Summarize the results.

f(x) = 4 x^4 - 2 x^3 + x - 5 has one global minimum:

Answer: f(x) has a global minimum at x = -0.303504

5 0
3 years ago
Read 2 more answers
What is the volume of a box that will hold exactly 567 of these cubes with 1/3 inch sides?
Viktor [21]
Let’s find the volume of the small cubes.
1/3^3
1/27
Now multiply this by 567
567•(1/27)
21
The volume of the box is 21 inches cubed.
8 0
3 years ago
What are the solutions to the system of equations? y=x2−7x+12y=−x+7
kap26 [50]

Answer:

x = 1, y = 6

or

x = 5, y = 2.

Step-by-step explanation:

y=x2−7x+12

y=−x+7

Substitute for y in the first equation:

- x + 7 = x^2 - 7x + 12

x^2 - 7x + x + 12 - 7 = 0

x^2 - 6x + 5 = 0

(x - 1)(x - 5) = 0

x = 1, 5.

When x = 1, y = -1 + 7 = 6.

when x = 5, y = -5+7 = 2.

3 0
2 years ago
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