Question 5 (3 points)

Select the correct answer from each drop-down menu.

ohaa [14]

Answer:

y = -x + 17

Step-by-step explanation:

A(-10,-3)

B(7,14)

C(5,12)

Need line CD perpendicular to AB through C.

Solution:

slope of AB, m1 = (yb-ya) / (xb-xa) = (14- -3) / (7- -10) = 17/17 = 1

Slope of CD, m2 = -1/m1 = -1 / 1 = -1

Line CD through C, using the point slope form

y-yc = m2(x-xc)

y-12 = -1 (x-5)

rearrange

y = -x + 5 + 12

y = -x + 17

5 0

3 years ago

Help help please please

svlad2 [7]

Answer:

$\sqrt{97}$

Step-by-step explanation:

becauseby pytagorean theorem we get

${4}^{2} + {9 = c}^{2}$

16+81=c squared

97 =c squared

c=radical 97

4 0

3 years ago

Tom is trying to write 3/61 as a decimal. He used long division and divided until he got the quotient 0.0491803279, at which poi

PilotLPTM [1.2K]

45,678,689 & [56 witch I think

5 0

4 years ago

Read 2 more answers

To make Harry potters gryffindor crest cumings used 20 gold , 10 white and 4 jelly beans what type of ratio is it ?

scoray [572]

Answer:

This is a three-term ratio

Step-by-step explanation:

There's three quantities, right? Simple my dude

20:10:4

8 0

4 years ago

Five individuals from an animal population thought to be near extinction in a certain region have been caught, tagged, and relea

Talja [164]

Answer:

a) For this case the random variable X follows a hypergometric distribution.

b) $E(X)= n\frac{M}{N}=10 \frac{5}{25}=2$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}=10\frac{5}{25}\frac{25-5}{25}\frac{25-10}{25-1}=1$

c) $P(X=0)= \frac{(5C0)(25-5 C 10-0)}{25C10}=\frac{1*184756}{3268760}=0.0565$

d) $P(X=5)= \frac{(5C5)(25-5 C 10-5)}{25C10}=\frac{1*15504}{3268760}=0.00474$

Step-by-step explanation:

The hypergometric distribution is a discrete probability distribution that its useful when we have more than two distinguishable groups in a sample and the probability mass function is given by:

$P(X=k)= \frac{(MCk)(N-M C n-k)}{NCn}$

Where N is the population size, M is the number of success states in the population, n is the number of draws, k is the number of observed successes

The expected value and variance for this distribution are given by:

$E(X)= n\frac{M}{N}$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}$

a. What is the distribution of X?

For this case the random variable X follows a hypergometric distribution.

b. Compute the values for E(X) and Var(X)

For this case n=10, M=5, N=25, so then we can replace into the formulas like this:

$E(X)= n\frac{M}{N}=10 \frac{5}{25}=2$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}=10\frac{5}{25}\frac{25-5}{25}\frac{25-10}{25-1}=1$

c. What is the probability that none of the animals in the second sample are tagged?

So for this case we want this probability:

$P(X=0)= \frac{(5C0)(25-5 C 10-0)}{25C10}=\frac{1*184756}{3268760}=0.0565$

d. What is the probability that all of the animals in the second sample are tagged?

So for this case we want this probability:

$P(X=5)= \frac{(5C5)(25-5 C 10-5)}{25C10}=\frac{1*15504}{3268760}=0.00474$

4 0

3 years ago