Question 5 (3 points)
1 answer:
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Length of circular track is:
L = 2*r*pi
He run 3/4 of it so length is:
L' = 3*2/4*r*pi = 3/2*r*pi
To calculate speed of his movement we use formula:
v = s/t where s = L' and t = 1 minute 45 seconds = 105 seconds
v = L'/t = 3*r*pi/2*105
v = r* pi/70
If we take that r = 1
answer
L = 2*r*pi
He run 3/4 of it so length is:
L' = 3*2/4*r*pi = 3/2*r*pi
To calculate speed of his movement we use formula:
v = s/t where s = L' and t = 1 minute 45 seconds = 105 seconds
v = L'/t = 3*r*pi/2*105
v = r* pi/70
If we take that r = 1
answer
Answer:
7miles
equations shown in work image below
work shown on the paper with more explanations because text is hard to write equations (sorry I used km but it is miles for your problem.)
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and brainliest crown :)
Step-by-step explanation:
For both d=r*t
Each bikes to others house and leave at the same time so for Tony,
11 = 30*t
t= 11/30 hours
for Gerry,
11 = 25*t
t= 11/25 hours
Comparing these, with LCD,
Tony's time is 55/150
Gerry's time is 66/150
So Tony got to Gerry's house 11/150 hours quicker than Gerry got to Tony's house.
Now they turn around and head back toward each other. If they leave at the same exact time, the elapsed time for each until they met would be the same so t (for tony) = t (for gerry), but Tony got a head start.
We start the stopwatch when Gerry turns around 11/150 hours after Tony has turned around. If Gerry's time to where they meet from Tony's house t(gerry), then Tony's time from Gerry's house is t(gerry) + 11/150
