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WARRIOR [948]
3 years ago
6

In algeb, what is 4^x=64?

Mathematics
1 answer:
ivolga24 [154]3 years ago
4 0
Hi

Here are the steps

4^x = 64
First, we need to solve for the exponent
log(4^x) = log(64)
Now we need to take log of
x * (log(4)) = log(64)
x = log(64)/(log(4)
x= 3


Here you go guys :)

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Add and simplify 1/5 + 1/10
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1/5 can turn into 2/10 Its the same thing. And its easier to solve with.

now lets multiply.

\frac{2}{10} × \frac{1}{10}

Now we add across

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10 + 10 = 10 ( When adding fractions like these the denominator stays the same)

So your answer is...

\frac{3}{10}

Good Luck! :)

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This thing appears in the Bhaskara's formula for the roots of the quadratic equation:

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You can see that the determinant is inside a square root, this means that if D is smaller than zero we will have imaginary roots (the graph never touches the x-axis)

If D = 0, the square root term dissapear, and this implies that both roots of the equation are the same, this means that the graph touches the x axis in only one point, wich coincides with the minimum/maximum of the graph)

If D > 0 we have two different roots, so the graph touches the x-axis in two different points.

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Please help me with this
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CD= 34

Step-by-step explanation:

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3 years ago
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