im pretty sure the answer is C
y=3x-2
Change them side
3x-2=y
Add 2 to both sides
3x-2+2=y+2
3x=y+2
Divide both sides by 3 so we can find the x value
3x/3= y+2/3
x= 1/3 y + 2/3
I hope that's help:0
First, you subtract 15 on each side:
2/3x=17-15
then, you simplify:
2/3x=2
multiply by 3
2x=6
divide by 2
x=3
Answer:
c. observed values of the independent variable and the predicted values of the independent variable
Step-by-step explanation:
This helps us, for example, find the values of y in a y = f(x) equation. y is dependent of x. So x is the independent variable and y the dependent. Obviously, this system is used for way more complex equations, in which is hard to find an actual pattern for y, so we use this method to compare the predicted values of y to the observed.
The correct answer is:
c. observed values of the independent variable and the predicted values of the independent variable
Problem 1
<h3>Answer: 7/10</h3>
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Explanation:
The formula we'll use is
P(A or B) = P(A) + P(B)
which only works if A and B are mutually exclusive events.
P(A or B) = P(A) + P(B)
P(A or B) = 7/20 + 7/20
P(A or B) = (7+7)/20
P(A or B) = 14/20
P(A or B) = (7*2)/(10*2)
P(A or B) = 7/10
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Problem 2
<h3>Answer: 3/4</h3>
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Explanation:
We'll use the same formula as the previous problem.
P(A or B) = P(A) + P(B)
P(A or B) = 3/10 + 9/20
P(A or B) = 6/20 + 9/20
P(A or B) = (6+9)/20
P(A or B) = 15/20
P(A or B) = (3*5)/(4*5)
P(A or B) = 3/4
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Problem 3
<h3>Answer: 3/5</h3>
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Explanation:
We'll use the same formula as the previous problem.
P(A or B) = P(A) + P(B)
P(A or B) = 7/20 + 1/4
P(A or B) = 7/20 + 5/20
P(A or B) = (7+5)/20
P(A or B) = 12/20
P(A or B) = (4*3)/(4*5)
P(A or B) = 3/5
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Problem 4
<h3>Answer: 0</h3>
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Explanation:
This time we're asked to find P(A and B), but since the two events are mutually exclusive, this means the probability of both occurring is 0.
Mutually exclusive events cannot happen simultaneously.
An example would be flipping heads and tails at the same time on the same coin.
The info about P(A) and P(B) is not relevant.