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3 years ago

Solve for s. 2|s| = 18

1 answer:

5 0

2|s| = 18

First, divide both sides by 2. / Your problem should look like: |s| = $\frac{18}{2}$
Second, simplify $\frac{18}{2}$ to 9. / Your problem should look like: |s| = 9
Third, break down the problem into these 2 equations. / s = 9 and -s = 9
Fourth, solve the 1st equation: s = 9.
Fifth, solve the 2nd equation: s = -9
Sixth, collect your solutions. / Your problem should look like: s = <span>±9
</span>
Answer: D) s = -9 and s = 9

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AleksandrR [38]

im pretty sure the answer is C

5 0

3 years ago

Find the unique value of y =3x-2

Tatiana [17]

y=3x-2

Change them side

3x-2=y

Add 2 to both sides

3x-2+2=y+2

3x=y+2

Divide both sides by 3 so we can find the x value

3x/3= y+2/3

x= 1/3 y + 2/3

I hope that's help:0

6 0

4 years ago

I need help with this equation

poizon [28]

First, you subtract 15 on each side:
2/3x=17-15
then, you simplify:
2/3x=2
multiply by 3
2x=6
divide by 2
x=3

8 0

3 years ago

Application of the least squares method results in values of the y-intercept and the slope that minimizes the sum of the squared

vaieri [72.5K]

Answer:

c. observed values of the independent variable and the predicted values of the independent variable

Step-by-step explanation:

This helps us, for example, find the values of y in a y = f(x) equation. y is dependent of x. So x is the independent variable and y the dependent. Obviously, this system is used for way more complex equations, in which is hard to find an actual pattern for y, so we use this method to compare the predicted values of y to the observed.

The correct answer is:

c. observed values of the independent variable and the predicted values of the independent variable

5 0

3 years ago

Can you find the probability to each of these answers...

goldfiish [28.3K]

Problem 1

<h3>Answer: 7/10</h3>

-----------------------

Explanation:

The formula we'll use is

P(A or B) = P(A) + P(B)

which only works if A and B are mutually exclusive events.

P(A or B) = P(A) + P(B)

P(A or B) = 7/20 + 7/20

P(A or B) = (7+7)/20

P(A or B) = 14/20

P(A or B) = (7*2)/(10*2)

P(A or B) = 7/10

=========================================================

Problem 2

<h3>Answer: 3/4</h3>

-----------------------

Explanation:

We'll use the same formula as the previous problem.

P(A or B) = P(A) + P(B)

P(A or B) = 3/10 + 9/20

P(A or B) = 6/20 + 9/20

P(A or B) = (6+9)/20

P(A or B) = 15/20

P(A or B) = (3*5)/(4*5)

P(A or B) = 3/4

=========================================================

Problem 3

<h3>Answer: 3/5</h3>

-----------------------

Explanation:

We'll use the same formula as the previous problem.

P(A or B) = P(A) + P(B)

P(A or B) = 7/20 + 1/4

P(A or B) = 7/20 + 5/20

P(A or B) = (7+5)/20

P(A or B) = 12/20

P(A or B) = (4*3)/(4*5)

P(A or B) = 3/5

=========================================================

Problem 4

<h3>Answer: 0</h3>

-----------------------

Explanation:

This time we're asked to find P(A and B), but since the two events are mutually exclusive, this means the probability of both occurring is 0.

Mutually exclusive events cannot happen simultaneously.

An example would be flipping heads and tails at the same time on the same coin.

The info about P(A) and P(B) is not relevant.

7 0

4 years ago