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ivanzaharov [21]
3 years ago
10

5.

Mathematics
1 answer:
Alenkasestr [34]3 years ago
7 0

Answer: the answer is C which is .0287

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Help plz you Smart people
Nitella [24]

Answer:

y < -1.2

Step-by-step explanation:

Hii,

4/3 < -8/3 y

To get y by itself, you need to divide by -8/3 on both sides...

4/3 divided by -8/3 is the same thing as...

4/3 x -3/8

(when dividing fractions, simply flip the second fraction and multiply straight across)

After that, you get -12/24 which is the same thing as -1/2.

Since you divided by a negative, the inequality sign flips.

So...

-1/2 < y

is...

y < -1/2

Hope this helps!

7 0
3 years ago
Read 2 more answers
PERCENTS!! <br><br> due today help!!!! (:
kvv77 [185]
The answer is C. $144
6 0
3 years ago
Determine the next step for solving the quadratic equation by completing the square.
nexus9112 [7]

\qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2

the idea behind the completion of the square is simply using a perfect square trinomial,  hmmm usually we do that by using our very good friend Mr Zero, 0.

if we look at the 2nd step, we have a group as x² - x, hmmm so we need a third element, which will be squared.

keeping in mind that the middle term of the perfect square trinomial is simply the product of the roots of "a" and "b",  so in this case the middle term is "-x", and the 1st term is x², so we can say that

\stackrel{middle~term}{2(\sqrt{x^2})(\sqrt{b^2})~}~ = ~~\stackrel{middle~term}{-x}\implies 2xb~~ = ~~~~ = ~~-x \\\\\\ b=\cfrac{-x}{2x} \implies b=-\cfrac{1}{2}

so that means that our missing third term for a perfect square trinomial is simply 1/2, now we'll go to our good friend Mr Zero, if we add (1/2)², we have to also subtract (1/2)², because all we're really doing is borrowing from Zero, so we'll be including then +(1/2)² and -(1/2)², keeping in mind that 1/4 - 1/4 = 0, so let's do that.

-3~~ = ~~-2\left[ x^2-x+\left( \cfrac{1}{2} \right)^2 ~~ - ~~\left( \cfrac{1}{2} \right)^2\right]\implies -3=-2\left(x^2-x+\cfrac{1}{4}-\cfrac{1}{4} \right) \\\\\\ -3=-2\left(x^2-x+\cfrac{1}{4} \right)+(-2)-\cfrac{1}{4}\implies -3=-2\left(x^2-x+\cfrac{1}{4} \right)+\cfrac{1}{2} \\\\\\ -3-\cfrac{1}{2}=-2\left(x^2-x+\cfrac{1}{4} \right)\implies -\cfrac{7}{2}=-2\left(x-\cfrac{1}{2} \right)^2\implies \cfrac{7}{4}=\left(x-\cfrac{1}{2} \right)^2

~\dotfill\\\\ \pm\sqrt{\cfrac{7}{4}}=x-\cfrac{1}{2}\implies \cfrac{\pm\sqrt{7}}{2}=x-\cfrac{1}{2}\implies \cfrac{\pm\sqrt{7}}{2}+\cfrac{1}{2}=x \implies \cfrac{\pm\sqrt{7}+1}{2}=x

8 0
2 years ago
Can you Graph y= 2/3x -4, please
mel-nik [20]

Quite a vague question, I used desmos to graph the attached photo.

3 0
4 years ago
Factoring polynomial. Is there a GCF? Please do number 1
Dahasolnce [82]
I believe the GCF is 5rs^2
7 0
3 years ago
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