Write an inequality and show on a number line all numbers:from (–3) to 2 exclusive.
1 answer:
Answer:
Step-by-step explanation:
Given:
Range: -3 to 2
Required:
- Write the inequality
- Represent on a number line
Let the variable be represented by x
The question says -3 and 2 are exclusive of x;
This implies that, -3 is less than x and at the same time x is less than 2
Write out the two inequalities
and
Combine both inequalities
See attachment for number line
<em>Notice that the circle on -3 and 2 are </em><em>opened</em>
<em>This implies that -3 and 2 are exclusive of the inequality;</em>
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Answer:
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Step-by-step explanation:
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The area of the shaded region will be the subtraction of the area of the two smaller circles from the area of the larger circle.
As such:
Answer:
We can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.
Step-by-step explanation:
We have to find how many passwords with 4 different digits can we write with the numbers 1, 2, 3, 4, 5, and 6.
Firstly, it must be known here that to calculate the above situation we have to use Permutation and not combination because here the order of the numbers in a password matter.
Since we are given six numbers (1, 2, 3, 4, 5, and 6) and have to make 4 different digits passwords.
- Now, for first digit of the password, we have 6 possibilities (numbers from 1 to 6).
- Similarly, for second digit of the password, we have 5 possibilities (because one number from 1 to 6 has been used above and it can't be repeated).
- Similarly, for the third digit of the password, we have 4 possibilities (because two numbers from 1 to 6 have been used above and they can't be repeated).
- Similarly, for the fourth digit of the password, we have 3 possibilities (because three numbers from 1 to 6 have been used above and they can't be repeated).
So, the number of passwords with 4 different digits we can write = = 360 possibilities.
Hence, we can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.