Given:
The area of a rectangle = 14 square units.
The side lengths are a and b.
![a=2\dfrac{1}{3}](https://tex.z-dn.net/?f=a%3D2%5Cdfrac%7B1%7D%7B3%7D)
To find:
The value of b.
Solution:
We know that, the area of a rectangle is:
![Area=Length\times Width](https://tex.z-dn.net/?f=Area%3DLength%5Ctimes%20Width)
The area of the given rectangle is:
![14=a\times b](https://tex.z-dn.net/?f=14%3Da%5Ctimes%20b)
![14=2\dfrac{1}{3}\times b](https://tex.z-dn.net/?f=14%3D2%5Cdfrac%7B1%7D%7B3%7D%5Ctimes%20b)
![14=\dfrac{2(3)+1}{3}b](https://tex.z-dn.net/?f=14%3D%5Cdfrac%7B2%283%29%2B1%7D%7B3%7Db)
![14=\dfrac{6+1}{3}b](https://tex.z-dn.net/?f=14%3D%5Cdfrac%7B6%2B1%7D%7B3%7Db)
On further simplification, we get
![14=\dfrac{7}{3}b](https://tex.z-dn.net/?f=14%3D%5Cdfrac%7B7%7D%7B3%7Db)
![14\times 3=7b](https://tex.z-dn.net/?f=14%5Ctimes%203%3D7b)
![42=7b](https://tex.z-dn.net/?f=42%3D7b)
Divide both sides by 7.
![\dfrac{42}{7}=b](https://tex.z-dn.net/?f=%5Cdfrac%7B42%7D%7B7%7D%3Db)
![6=b](https://tex.z-dn.net/?f=6%3Db)
Therefore, the value of b is 6 units.
Answer:
C. I & III
Step-by-step explanation:
I simplifies to ...
2(6x +15 -5x) +4 = 40
12x +30 -10x +4 = 40
2x +34 = 40
__
II simplifies to ...
40 = 2(15 -x) +4
40 = 30 -2x +4
40 = -2x +34 . . . . . . not equivalent to I (sign of x-term is different)
__
III simplifies to ...
12x +30 -10x +4 = 40
2x +34 = 40 . . . . . . equivalent to I
___
I & III are equivalent
63/h-14. Twenty characters to make the brainliacs happy.
The answer would be 18.05
If she started out with 100 and she added 5 groups of 10 she should have 150.
100+(5 x 10)
50
100+50=150