All categories

3 years ago

Simplify: 45÷3+2×8-12+30

Mathematics

2 answers:

Vikentia [17]3 years ago

7 0

Answer:

61 is the answer

Step-by-step explanation:

Phantasy [73]3 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

Verne has two pieces of lumber the redwood board is 3/4 inch thick. The pine board is only 1/5 inch thick. How much thicker is t

Mice21 [21]

Answer:

SteThe redwood is 3.75 times thicker

p-by-step explanation:

7 0

2 years ago

125.638 rounded to nearest hundred

sineoko [7]

125.638 rounded to the nearest hundredth equal 125.64

5 0

3 years ago

Read 2 more answers

A triangle T is bounded (on three sides) by the lines x = 6, y = 0, and y = 3 2 x. A rectangle of width w is inscribed inside T.

Viktor [21]

Answer:

33.85 units^2

Step-by-step explanation:

you must first draw the triangle on the plane using the equations (see

attached file), you will have a right angle triangle with a height of 192 and a base of 6.

then you calculate the angle with the tangent function = 88.21

Then you use the small triangle to find the value of a (see attached file).

Finally, you propose an equation for X to find one of the sides of the triangle, once you have x squared it, and you already have the area,

i attached procedure

7 0

3 years ago

Find the missing length of the solid figure. 3 m 3 m 8 m

ahrayia [7]

Please put the image so I can see and help.

5 0

3 years ago

From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th

wel

Answer:

$\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}$

Step-by-step explanation:

The width of a square is its side length.

The width of a circle is its diameter.

Therefore, the largest possible circle that can be cut out from a square is a circle whose diameter is equal in length to the side length of the square.

Formulas

$\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}$

$\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}$

$\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}$

If the diameter is equal to the side length of the square, then:
$\implies \sf r=\dfrac{1}{2}s$

Therefore:

$\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}$