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3 years ago

How would I find 10% of 30 by using a proportion?

2 answers:

6 0

Set up an proportion first. It looks like this:

Part Percent
————— = —————
Whole 100%
10 is your percent, 30 is your whole, 100 is always 100, and you don’t know the part so it is x (unknown).
It now looks like this:
X 10
————— = —————
30% 100%

Step by step explanation:

1) multiply across
30 • 10 = 300

2) divide what’s left over
300 / 100 = 3
So 10% of 30 is 3.

Zepler [3.9K]3 years ago

3 0

10% × 30 =

(10 ÷ 100) × 30 =

(10 × 30) ÷ 100 =

300 ÷ 100 =

You might be interested in

What is the Y value of the point that Partitions the directed line segment A.B. into a 1:3 ratio

xenn [34]

Answer:

y = 5

Step-by-step explanation:

AB = | 8 - (- 4) | = | 12 |= 12

Divide 12 by the sum of the parts of the ratio, 1 + 3 = 4

12 ÷ 4 = 3

Thus

y = 8 - 3 = 5

5 0

2 years ago

Here's the question.

OleMash [197]

Answer:

The value of T₂₀ - T₁₅ is -20.

Step-by-step explanation:

Given :

>> If for an A.P, d = -4

To Find :

>> T₂₀ - T₁₅

Using Formula :

General term of an A.P.

$\star{\small{\underline{\boxed{\sf{\red{ T_n = a + (n - 1)d}}}}}}$

>> Tₙ = nᵗʰ term
>> a = first term
>> n = no. of terms
>> d = common difference

Solution :

Firstly finding the A.P of T₂₀ by substituting the values in the formula :

${\dashrightarrow{\pmb{\sf{ T_n = a + (n - 1)d}}}}$

${\dashrightarrow{\sf{ T_{20} = a + (20 - 1) d}}}$

${\dashrightarrow{\sf{ T_{20} = a + (19)d}}}$

${\dashrightarrow{\sf{ T_{20} = a + 19 \times d}}}$

${\dashrightarrow{\sf{ T_{20} = a + 19d}}}$

${\star \: {\underline{\boxed{\sf{\pink{ T_{20} = a + 19d}}}}}}$

Hence, the value of T₂₀ is a + 19d.

$\rule{190}1$

Secondly, finding the A.P of T₁₅ by substituting the values in the formula :

${\dashrightarrow{\pmb{\sf{ T_n = a + (n - 1)d}}}}$

${\dashrightarrow{\sf{ T_{15}= a + (15 - 1) d}}}$

${\dashrightarrow{\sf{ T_{15}= a + (14) d}}}$

${\dashrightarrow{\sf{ T_{15}= a + 14 \times d}}}$

${\dashrightarrow{\sf{ T_{15}= a + 14d}}}$

${\star{\underline{\boxed{\sf \pink{ T_{15}= a + 14d}}}}}$

Hence, the value of T₁₅ is a + 14d

$\rule{190}1$

Now, finding the difference between T₂₀ - T₁₅ :

${\dashrightarrow{\pmb{\sf{T_{20} - T_{15}}}}}$

${\dashrightarrow{\sf{(a + 19d) - (a + 14d)}}}$

${\dashrightarrow{\sf{a + 19d - a - 14d}}}$

${\dashrightarrow{\sf{a - a + 19d - 14d}}}$

${\dashrightarrow{\sf{0+ 19d - 14d}}}$

${\dashrightarrow{\sf{19d - 14d}}}$

${\dashrightarrow{\sf{5 \times - 4}}}$

${\dashrightarrow{\sf{ - 20}}}$

${\star \: \underline{\boxed{\sf{\pink{T_{20} - T_{15} = - 20}}}}}$

Hence, the value of T₂₀ - T₁₅ is -20.

$\underline{\rule{220pt}{3.5pt}}$

3 0

2 years ago

HELPPP. DO TODAY SO PLEASE HELP!!!!!!!!!!

oksian1 [2.3K]

Answer:

47/6cm or $7\frac{5}{6}$ cm

Step-by-step explanation:

FE= $2\frac{2}{3}$

FA= 5/12

AB= 2/3

CD=2

ED= $1\frac{1}{4}$

BC= 5/6

All=47/6 or $7\frac{5}{6}$

6 0

2 years ago

(PLEASE ANSWER ASAP) Which number is between 1/6 and 0.25?

serg [7]

If you change both to a fraction you would see that you have 1/6 and 1/4 (.25 as a fraction). So 1/5 would be in between them.

You could also change both as a decimal. 1/6 =.166666 and .25 so any number in between them would be correct such as .2 which is the same as 1/5.

8 0

3 years ago

The floor of a room is being covered with tile. An area one half

tangare [24]

Answer:

Only the floor area $\frac{3}{8}$ has been covered

Step-by-step explanation:

Assuming that the floor of the room is rectangular, then its area is equal to the product of its length times its width.

$A = lw$

Let's now call A 'the area that was covered with tiles.

We know that half the length was covered, then:

$l' = \frac{1}{2}l$

$w' = \frac{3}{4}w$

So:

$A' = \frac{1}{2}l(\frac{3}{4}w)$

$A' = \frac{3}{8}lw$

Finally:

$A' = \frac{3}{8}A$

4 0

2 years ago