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jeyben [28]
3 years ago
6

the equation of a line is y=-1/2x-2. what is the equation of the line that is perpendicular to the first line and passes through

the point (2, –2)?
Mathematics
1 answer:
Alexxandr [17]3 years ago
8 0
Perpendicular means that the slopes are negartive inverses, aka
slope1 times slope2=-1

y=mx+b
slope=m

y=-1/2x-2
slope=-1/2

we need to find negative inverse
-1/2 times what=-1
answer is 2

y=2x+b
input the point (2,-2) to find b
(x,y)
(2,-2)
-2=2(2)+b
-2=4+b
minus 4 from both sides
-6=b
y=2x-6

the equtaion is y=2x-6
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<h3>The constant of proportionality is k = 5</h3>

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Another example: the point (x,y) = (6, 30) is also on the same diagonal line, so k = y/x = 30/6 = 5 is the same result as before.

You can use any point on the diagonal line as long as it is not (0,0). This is because division by zero is not allowed.

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