Given A(-3, 6) and B(0, 6), what are the coordinates of point P that lies on segment AB, such that AP:PB = 2:1? A: (2, -2) B: (-
1 answer:
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Answer:
y = 4 sin( 0.5t - ) - 2
y = a sin ( 2t - ) + 2
Step-by-step explanation:
In the first question,
amplitude = 4
Period =
phase shift =
Vertical shift = -2
Angular velocity , w =
Here, w = = 0.5
The general equation of a wave is
y = a sin( wt + ∅ )
Putting above values in the equation,
y = 4 sin( 0.5t - ) - 2
In the second question,
Amplitude is not given so we will take it as a.
time period =
w = 2
Phase shift =
Vertical shift = 2
The equation is
y = a sin ( 2t - ) + 2
Answer:
y = -3 m = -1 b = 3
Step-by-step explanation:
-3y=3x-9
To isolate the y variable, divide both sides by -3.
y = -1x + 3
y = -3
m = -1
b = 3
