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OLEGan [10]
4 years ago
6

Please help me!!! I will give you brainiest.

Mathematics
1 answer:
alexdok [17]4 years ago
5 0
F(x) transformed into g(x), the square root turned in to 3 square root and x is being -2 in the 3 square root and the then is being added by 5 so there’s how it transformed in to that function I’m probably wrong but that’s what I think
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The lines represented by the equations 2y - 3x = 14 and y - 3/2x= 7 are
zhenek [66]

Answer:

00000

Step-by-step explanation:

3 0
3 years ago
Can someone please tell me what range and domain is. and how to tell what an independent and dependent variable are please
Elis [28]

Answer: The dependent variable is the Y axis of a graph, or the side of the graph that is vertical. The independent variable is the X axis of a graph, or the side of the graph that is horizontal. Domain is the input of a mathematical function, and the range is the output!

Hope this helps :)

8 0
3 years ago
Read 2 more answers
Jillian walked 0.5 miles before she started jogging at an average pace of 5 miles per hour. The equation d = 0.5 + 5t can be use
castortr0y [4]

Answer:

The answer is option 2.

Step-by-step explanation:

In the question, the independent variable is time and dependent is distance. As the time changes, the distance will also change it means the distance depends on time.

For example,

d = 0.5 + 5t

Let t = 1,

d = 0.5 + 5(1)

d = 5.5 \: miles

Let t = 5,

d = 0.5 + 5(5)

d = 25.5 \: miles

Therfore, as time increases, distance will also increase.

4 0
4 years ago
Simplify the expression to a + bi form:<br> (2 – i) – (-4+8i)
Ne4ueva [31]

Answer:

6-9i

Step-by-step explanation:

(2-i)-(-4+8i)

2-i+4-8i

2+4-i-8i

6-i-8i

6-9i

If you're satisfied with the answer, then please mark me as Brainliest.

8 0
3 years ago
Read 2 more answers
Answer two questions about Equations AAA and BBB:\begin{aligned} A.&amp;&amp;5x&amp;=3x \\\\ B.&amp;&amp;5&amp;=3 \end{aligned}A
max2010maxim [7]

Answer:

mulitply and divide by both sides

and yes

Step-by-step explanation:

6 0
3 years ago
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