10^6 = 1,000,000
10^2 = 100
1,000,000 / 100 = 10,000
so 8.76x10^6 is 10,000 times greater than
The graphed function, F(x), has a value greater than 0 over the intervals (-0.7, 0.76) and (0.76, ∞) . F(x) > 0 over the intervals (-0.7, 0.76) and (0.76, ∞) is the correct statement [Fourth choice].
About a Graphed Function
The function graph of an object F stands for the set of all points in the plane that are (x, f(x)). The graph of f is also known as the graph of y = f. (x). The graph of an equation is thus a specific example of the graph of a function. A graphed function is a function that has been drawn out on a graph.
It is evident from the attached graph that the supplied function exceeds 0 for the following range:
-0.7 < F(x) < 0.76
And, 0.76 < F(x) < ∞
As a result, the intervals for which the given graphed function, F(x) is greater than 0 are as follows,
(-0.7, 0.76) and (0.76, ∞)
Learn more about a graphed function here:
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Answer:
A) 0
Step-by-step explanation:
When x is divided by 11, we have a quotient of y and a remainder of 3
x/11 = y + 3
x = 11y + 3 ........(1)
When x is divided by 19, we have a remainder of 3 also
x/19 = p + 3 (p = quotient)
x = 19p + 3 ..........(2)
Equate (1) and (2)
x = 11y + 3 = 19p + 3
11y + 3 = 19p + 3
11y = 19p + 3 -3
11y = 19p
Divide both sides by 11
11y/11 = 19p/11
y = 19p/11
y and p are integers. 19 is a prime number. P/11 is also an integer
y = 19(integer)
This implies that y is a multiple of 19. When divided by 19, there is no remainder. The remainder is 0
Answer:
2. 4
Step-by-step explanation:
use the formula A=ab/2
a-leg 1
b-leg 2 (base)
since it is a right triangle the height would be 2 cm and the base would be the leg (4 cm)
plus into the equation- A= 2(4)/2
8/2=4
The numbers inside the parenthesis is the value of x, uses the equation associated with the value of x and solve.
H(1) Since 1 fits 1≤x≤3 use x^3
x^3 1^3 = 1
h(1) = 1
h(4) 4 fits x >3, so use 5
h(4) = 5
