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Deffense [45]
3 years ago
6

Ten times the quotient of 104 and 88

Mathematics
1 answer:
lilavasa [31]3 years ago
6 0
11.82 which is closest to 12, would be the answer to ten times the quotient of 104 and 88.

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Alika [10]
You would get 89/21 and then for a mixed number 4& 5/21
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3 years ago
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What is the value of X?
rodikova [14]

Answer:

102

Step-by-step explanation:

triangle area = 180 degrees

straight line = 180 degrees

180 - 127 = 53

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3rd angle = 78

180-78 = x

x = 102

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2 years ago
Polly and Percy were sharing a bag ofjelly beans. The bag contained 52 orange, 63 lime, 72 cherry, 28 lemon and 65 grape. If Pol
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b

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3 years ago
One Sunday, 120 days before Christmas, Aldsworth store publishes an advertisement saying ‘120 shopping days until Christmas'. Al
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Answer:

(a)18

(b)1089

(c)Sunday

Step-by-step explanation:

The problem presented is an arithmetic sequence where:

  • First Sunday, a=1
  • Common Difference (Every subsequent Sunday), d=7

We want to determine the number of Sundays in the 120 days before Christmas.

(a)In an arithmetic sequence:

\text{The nth term}, T_n=a+(n-1)d\\T_n \leq 120\\$Therefore:$\\1+7(n-1) \leq 120\\1+7n-7\leq 120\\7n-6\leq 120\\7n\leq 120+6\\7n\leq 126\\$Divide both sides by 7$\\n\leq 18

Since the result is a whole number, there are 18 Sundays in which Aldsworth advertises.

Therefore, Aldsworth advertised 18 times.

(b)Next, we want to determine the sum of the first 18 terms of the sequence

1,8,15,...

\text{Sum of a sequence}, S_n=\frac{n}{2}( 2a+(n-1)d)\\S_{18}=\frac{18}{2}( 2*1+(18-1)*7)\\=9(2+17*7)\\=9(2+119)\\=9*121\\S_{18}=1089

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(c)SInce the 120th day is the 18th Sunday, Christmas is on Sunday.

6 0
3 years ago
You invest $1,200 in an account that pays an interest rate of 7.25%, compounded continuously.
hammer [34]
The answer is $1,809.00.

Explanation:

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Hope I helped and good luck!
6 0
3 years ago
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