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mihalych1998 [28]
3 years ago
15

May someone help please?

Mathematics
2 answers:
xeze [42]3 years ago
3 0
The 3rd option is exponential decay
Soloha48 [4]3 years ago
3 0

A 'decaying' function is one where 'y' gets smaller as 'x' gets bigger.
You might say that 'y' peters out as time goes on.

Each of the functions listed in this problem have kind of the same form.
For all of them, we can ignore the first fraction, and just look at the fraction
in the parentheses that's raised to the power of +x or -x.

What we're looking for is one that gets smaller and smaller as 'x' grows.
That has to be a fraction that starts out less than '1', so the more times
you multiply it by itself, the smaller it gets.

The only tricky trick here is to know how to handle the ones with the exponent -x .

Where you see a fraction raised to the -x power, you can flip the fraction over
and then change the power to just plain 'x'.

When you go down the list and examine each one, you find that the only one
that keeps getting smaller as 'x' keeps getting bigger is the 3rd one down.
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65%

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Write the following quotient in the form a+bi.<br> -7i/2-7i
Helga [31]

Answer:

\large\boxed{\dfrac{49}{53}-\dfrac{14}{53}i}

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
Wilhema bought 6 bars of soap for $12. The next day, Sophia bought 10 bars of the same kind of soap for $20. What is the cost of
kaheart [24]

Answer:

$2

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Hope this helps!


8 0
3 years ago
What is the cost of operating a 3.00-w electric clock for a year if the cost of electricity is $0.0900 per kw · h ?
brilliants [131]
We must take into account the following change of units:
 1kw = 1000w&#10;&#10;1 year = 365 days&#10;&#10;1 day = 24 hours
 Applying the change of units we have that the electric consumption for 1 year is given by:
 (3) * (1/1000) * (365) * (24) = 26.28 kw * h&#10;
 Then, the total cost is given by:
 (26.28) * (0.0900) = 2.3652&#10;
 Answer:
 
the cost of operating a 3.00-w electric clock for a year is:
 
$ 2.3652
8 0
3 years ago
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