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BabaBlast [244]
3 years ago
7

Solve the following systems using determinant (a) 2x +3y=4 4x +6y=4 ​

Mathematics
1 answer:
Wewaii [24]3 years ago
5 0

Answer:

it has no solution

Step-by-step explanation:

first of all if we want to know that how many solutions does it the system we can know easly

  • if a1/a2=b1/b2=c1/c2 then the system has infinite solution
  • if a1/a2=b1/b2≠c1/c2 the system has no solution
  • if a1/a2≠b1/b2 the system has no solution

so in this system a1=2,a2=4,b1=3,b2=6,c1=4&c2=4

so 2/4_3/6_4/4=(to becomfortable to compare we have to find the denominators LCM.LCM(4,6)=12

6/12=6/12≠12/12.

so the system has no solution.

&you can also solve by this way

2x+3y=4 (multiply by ‒2 to be y=0)

4x+6y=4

‒4x‒6y=‒8

4x+6y=4

= 0+0=‒4(error)

so it has no solution

i think it is clear & i hope it helps you.

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