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3 years ago

9. The side of a rectangle was 56 feet long. It is now 8 feet long. What was the scale factor was

Mathematics

1 answer:

Lynna [10]3 years ago

5 0

Answer:

56ft

Step-by-step explanation:

because 还是故事还是vs酒吧睡觉把书本上

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3 years ago

A quadratic function has a line of symmetry at x=-3.5 and zero at -9 what is the distance from the given zero to line of symmetr

g100num [7]

If a quadratic function has zero at x=-9, then point (-9,0) lies on the graph of quadratic function.

A line of symmetry has equation x=-3.5 that is x+3.5=0.

Use formula for the distance from point $(x_0,y_0)$ to the line AX+By+C=0:

$d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}}.$

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3 years ago

Alicia and Jeremy weigh a cell phone on a digital scale. They write down 113 but forget to record the unit. Which unit of measur

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I'm sure the measurement was made in grams because:

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3 years ago

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ASAP PLEASE ANSWER quadrilateral ABCD is dilated at center (0,0) with scale factor 1/2 to form quadrilateral A'B'C'D'. wha is th

zhenek [66]

Answer:

$|A'B'|=\sqrt{5}$

Step-by-step explanation:

The points A and B have coordinates at (0,4) and (4,2) respectively.

The distance formula can be used to find the length of AB.

$|AB|=\sqrt{(4-0)^2+(2-4)^2}$

$|AB|=\sqrt{(4)^2+(-2)^2}$

$|AB|=\sqrt{16+4}$

$|AB|=\sqrt{20}$

$|AB|=2\sqrt{5}$

Since quadrilateral ABCD was enlarged with a scale factor of $\frac{1}{2}$ .

The length of A'B' is

$\frac{1}{2}|AB|$

$=\frac{1}{2}\times2\sqrt{5}$

$\therefore |A'B'|=\sqrt{5}$

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3 years ago

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The answer is Y=2x+3

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3 years ago