Consider the attached figure. If AB has length 1, then BC has length sin(15°) and CD (the altitude of triangle ABC) has length sin(15°)·cos(15°).
By the double angle formula for sin(α), ...
... sin(2α) = 2sin(α)cos(α)
Rearranging, this gives
... sin(α)·cos(α) = sin(2α)/2
We have
... CD = sin(15°)·cos(15°) = sin(2·15°)/2
... CD = sin(30°)/2 = (1/2)/2 = 1/4
That is, the altitude, CD, is 1/4 the hypotenuse, AB, of triangle ABC.
Factors of 539:1, 7, 11, 49, 77, 539Factors of 1540:1, 2, 4, 5, 7, 10, 11, 14, 20, 22, 28, 35, 44, 55, 70, 77, 110, 140, 154, 220, 308, 385, 770, 1540
Common Factors: 1, 7, 11, 77GCF (greatest common factor) = 77
Hope this helps. :)
Answer:
−39
Step-by-step explanation:
−6^2+5−6−2
=−36+5−6−2
=−31−6−2
=−37−2
=−39
sorry Churchill stuff stuck see attached running stuff ooh stuck