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ohaa [14]
3 years ago
13

What is -4/4 +6 URGENT HELP PLSS

Mathematics
2 answers:
kaheart [24]3 years ago
7 0

To add fractions, find the LCD and then combine.

5

maxonik [38]3 years ago
3 0

Answer:

5

Step-by-step explanation:

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Find all values of the variable x for which the rational expression is undefined.
SashulF [63]

Answer:

Step-by-step explanation:

8x+9/x^2-13x+42

Write  8 x  as a fraction with denominator 1

8x+9/x^2-13x+42

then we multipuly 8x/1  by x^2/x^2

5 0
2 years ago
Can someone do 15?!?!?
andrew-mc [135]

<u>Given</u>:

The given triangle is a right triangle.

The length of the hypotenuse is 31 units.

The length of the leg is 23 units.

One of the angle is x.

We need to determine the value of x.

<u>Value of x:</u>

The value of x can be determined using the trigonometric ratio.

Thus, we have;

sin \ \theta=\frac{opp}{hyp}

Substituting \theta=x, the side opposite to the angle x measures 23 units and the hypotenuse is 31.

Thus, we have;

sin \ x=\frac{23}{31}

Dividing, we get;

sin \ x=0.74

Taking sin ^{-1} on both sides of the equation, we get;

x=sin^{-1}(0.74)

x=47.7

Rounding off to the nearest whole integer, we get;

x=48

Thus, the value of x is 48°

Hence, Option c is the correct answer.

5 0
3 years ago
ANSWER THIS ASAP DONT SEND A FILE AT ALL !! I NEED THE ANSWER TO QUESTION
jasenka [17]

Answer: just use phot math  

Step-by-step explanation:

4 0
3 years ago
Solve for x: - 4 + x &gt; 5
Rufina [12.5K]

Answer:

x>9 this is the correct answer

6 0
3 years ago
A river is flowing at the rate of 2.4 miles an hour when a boy rows across it. If the boy rows at a still-water speed of 3.1 mil
Xelga [282]

Answer:

3.9 mi/h

Step-by-step explanation:

If the boy is rowing perpendicular to the current, the two vectors form a right triangle.

AB represents the downstream current, BC is the speed across the river, and AC is the ground speed of the boat

AC^2 = 2.4^2 + 3.1^2 =5.76 + 9.61 = 15.37

AC = sqrt(15.37) = 3.9 mi/h

The boat's speed over the ground is 3.9 mi/h.

7 0
3 years ago
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