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MakcuM [25]
3 years ago
8

How do you solve (2x-7)(5x+3)=0

Mathematics
1 answer:
sammy [17]3 years ago
7 0

Step-by-step explanation:

First I do it as separate equations 2x-7=0 and 5x+3=0. In this equation you get two answers so you first answer 2x-7=0

2x-7=0

    +7   +7

2x=7

/2   /2

x=7/2

Then do 5x+3=0

                     -3  -3

                5x=-3

                    /5 /5

                x=  -3/5

Then you can check by putting them back in.

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Answer:

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The ratio opposite/adjacent is the ratio for tangent; this gives us the equation

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Use substitution. <br> 2x +3y = -5<br> 4x+3y= 17
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Answer:

Step-by-step explanation:

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