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Natali [406]
3 years ago
11

Joshua and his four friends have 1/2 pakage of a crackers. How many pakages of crackers do they have in all

Mathematics
1 answer:
maks197457 [2]3 years ago
7 0

answer:

2.5 or 2 1/2

work:

4(joshuas friends)+1(joshua)=5

5×1/2=5/2

5/2= 2.5

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Find the value of [-3/7] raised to the power -2<br><br> and (3) raised to the power -4
xenn [34]
(3)^-4 = 0.01234567901
(-3/7)^-2 = <span>5.44444444444</span>

7 0
3 years ago
Can someone explain how to do #3?
dsp73

\displaysyle (\sqrt 2)^{3}=(2^{\frac{1}{2}})^3=2^{\frac{1}{2} \cdot 3}=2^{\frac{3}{2}}=\sqrt {2^3}=\sqrt 8

√8 is between 2 and 3, because 2²=4<8, but 3²=9>8. Also, our value is closer to 3 than to 2, so it is more than 2.5 and we have C and D options left.

Among these two numbers we find the one which is closer to √8.

C. 27=√729 ⇒ 2.7=√7.29

D. 28=√784 ⇒ <u>2.8=√7.84</u>

Hence our answer is D) 2.8

5 0
4 years ago
Read 2 more answers
You roll a pair of number cubes.What is the probability of getting even numbers on both cubes?
andreev551 [17]

Answer:

1/4 or 25%

Step-by-step explanation:

Let's see, we want to know probability of an event in which we roll two even numbers.

"We know that probability is defined as number of desired outcomes divided by all possible outcomes"

e - even number

o - odd number

our desired outcome: (e, e) total of 1

all possible outcomes: (e, e), (e, o), (o, e), (o,o) total of 4

that gives us 1/4

8 0
4 years ago
an investment is expected to pay 5 per year compounded continuously. If you want the value of the investment to be $700,000 afte
andre [41]
The multiplier for continuous compounding is e^(rt). You want
  700,000 = P·e^(0.05·25) ≈ 3.490343P
Then
  700,000/3.490343 = P

You should invest $200,553 initially.
8 0
4 years ago
Help if correct ill mark brainlist!​
levacccp [35]

Answer:

B

Step-by-step explanation:

n - 4 = 4.5 - 4 = 0.5

8(n - 4) = 8 *(0.5 ) = 4

6 *n = 6 * 4.5 = 27

8(n - 4) + 6n

8(0.5) + 6*4.5

4 + 27

31

3 0
3 years ago
Read 2 more answers
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