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Lerok [7]
3 years ago
9

A rancher wants to fence in an area of 1,000,000 square feet in a rectangular field and then divide it in half with a fence down

the middle parallel to one side. Find a function that models the amount of fencing in terms of the width of the field, w, where w is the measurement of the fence down the middle of the field.
Mathematics
1 answer:
Svet_ta [14]3 years ago
5 0

Answer:

  f(w) = 3w + 2,000,000/w

Step-by-step explanation:

We know that the area of a rectangle is the product of its length and width:

  A = LW

Filling in the given values lets us write an expression for the length of the field.

  1,000,000 = Lw

  L = 1,000,000/w

Since there are 3 fences of length w and two of length L, the total perimeter fence length is the sum ...

  f(w) = 3w + 2(1,000,000)/w

Combining the constants, we have a function for the perimeter fence length in terms of the width of the field:

  f(w) = 3w +2,000,000/w

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If the sales tax in your city is 4.7\%4.7%4, point, 7, percent, and an item costs \$164$164dollar sign, 164 before tax, how much
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An accounting firm is planning for the next tax preparation season. From last years returns, the firm collects a systematic rand
Elena L [17]

Answer:

a)From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard error for the mean would be:

\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14

b) We want this probability:

P(\bar X >120)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

P( z>2.143) = 1-P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard error for the mean would be:

\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14

Part b

We want this probability:

P(\bar X >120)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

P( z>2.143) = 1-P(Z

4 0
3 years ago
Using the following equation, find the center and radius of the circle. You must show all work and calculations to receive credi
Oxana [17]

Answer:

Center: (-2, 4)

Radius: 4

Step-by-step explanation:

To find the centre and radius, we require to identify g , f and c

By comparing the coefficients of 'like terms' in the given equation with the general form.

2g = 4 → g = 2 , 2f = -8 → f = -4 and c = 4 → center=(−g,−f)=(−2,4)

radius = √22+(−4)2−4= √4+16−4=4

Center: (-2, 4)

Radius: 4

Hope This Helps! :)

8 0
3 years ago
Do u no the answer please help
Gre4nikov [31]
The answers are B) and E)

3 0
3 years ago
Read 2 more answers
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