What is 79x703 over 60to the second power

Which of the following expressions represents the total earnings of a commissioned employee earning 9.5% commission with sales o

Arte-miy333 [17]

9.5%= 0.095 since % means per 100.

Final answer: B

6 0

3 years ago

Read 2 more answers

Can someone help me ASAP

Len [333]

Answer:

-31 F = -35 C

-45 C = -49 F

-40 C = -40 F

City Y is coldest

Fahrenheit to Celsius conversion (°F to °C)

8 0

3 years ago

Based upon a smaller sample of only 170 st. paulites, what is the probability that the sample proportion will be within of the p

Pepsi [2]

Given that in 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hired by the Better Business Bureau to investigate the complaints they received this year involving new car dealers. You plan to select a sample of new car dealer complaints to estimate the proportion of complaints the Better Business Bureau is able to settle. Assume the population proportion of complaints settled for new car dealers is .75, the same as the overall proportion of complaints settled in 2008.

Part a) :

Suppose you select a sample of 450 complaints involving new car dealers. Show the sampling distribution of (to 4 decimals).

Population proportion = 0.75
sample size. n = 450
$Standard\ error=\sqrt{\frac{p(1-p)}{n}} \\ \\ =\sqrt{\frac{(0.75)(0.25)}{450}} = 0.0204$

Therefore, the sampling distribution has a proportion of 0.75 and a standard error of 0.0204.

Part b) :

Based upon a sample of 450 complaints, what is the probability that the sample proportion will be within .04 of the population proportion (to 4 decimals)?

The probability that the sample proportion will be within 0.04 of the population proportion is given by:

$P(p\ \textless \ 0.75\pm0.04)=2P\left(z\ \textless \ \frac{0.04}{0.0204} \right)-1 \\ \\ 2P(z\ \textless \ 1.961)-1=2(0.97505)-1=1.9501-1 \\ \\ =\bold{0.9501}$

Therefore, the probability that the sample proportion will be within .04 of the population proportion is 0.9501.

Part C:

Suppose you select a sample of 200 complaints involving new car dealers. Show the sampling distribution of (to 4 decimals).

Population proportion = 0.75
sample size. n = 200
$Standard\ error=\sqrt{\frac{p(1-p)}{n}} \\ \\ =\sqrt{\frac{(0.75)(0.25)}{200}} = 0.0306$

Therefore, the sampling distribution has a proportion of 0.75 and a standard error of 0.0306.

Part D):

Based upon the smaller sample of only 200 complaints, what is the probability that the sample proportion will be within .04 of the population proportion (to 4 decimals)?


The probability that the sample proportion will be within 0.04 of the population proportion is given by:

$P(p\
 \textless \ 0.75\pm0.04)=2P\left(z\ \textless \ \frac{0.04}{0.0306} 
\right)-1 \\ \\ 2P(z\ \textless \ 1.306)-1=2(0.90429)-1=1.80858-1 \\ \\
 =\bold{0.8086}$

Therefore, the probability that the sample proportion will be within .04 of the population proportion is 0.8086.

8 0

3 years ago

500+2000+45+338+2145

Semenov [28]

Answer:

5,028

Step-by-step explanation:

7 0

3 years ago

Plz Help!!!!!!!!!!!!!!!!!!!!!!!!!

Novosadov [1.4K]

Answer:

line segments j' k' and m' n' do not intersect and are the same distance apart as jk and mn

Step-by-step explanation:

this is because if jk and mn are both moved to the left two units, the space between them does not change

4 0

3 years ago