Question

find the point, M, that divides segment AB into a ratio of 5:2 if A is at (1,2) and B is at (8, 16).​

Answer 1

Answer:

Step-by-step explanation:

A(1,2) ---->(x1,y1)

B(8,16) ----->(x2,y2)

m:n = 5:2

$M(\frac{x_{2}m+x_{1}}{m+n},y_{2}m+y_{1}}{m+n})\\\\=M(\frac{5*8+2*1}{5+2},\frac{5*16+2*2}{5+2})\\\\=M(\frac{40+2}{7},\frac{80+4}{7})\\\\=M(\frac{42}{7}{,\frac{84}{7})\\\\=M(6,12)$