The total cost of 12 printers is; $493.41
Cost of first printer; C1 = $54
Cost of second printer is; 95% × 54 = $51.3
Cost of third printer is; 0.95 × 51.3 = $48.735
Cost of fourth printer = 0.95 × 48.735 = $46.298
Now, let us apply same pattern using a calculator for the remaining costs and we will have them as follows;
- Cost of 5th printer = $43.983
- Cost of 6th printer = $41.784
- Cost of 7th printer = $39.695
- Cost of 8th printer = $37.710
- Cost of 9th printer = $35.825
- Cost of 10th printer = $34.033
- Cost of 11th printer = $32.332
- Cost of 12th printer = $30.715
Total cost of the 12 printers is;
54 + 51.3 + 48.735 + 46.298 + 43.983 + 41.784 + 36.695 + 37.710 + 35.825 + 34.033 + 32.332 + 30.715 = $493.41
Read more about total costs of successive items at; brainly.com/question/16082169
Answer:
D
Step-by-step explanation:
To shift <em>h</em> units to the right, replace <em>x</em> with <em>x</em> - <em>h</em>
To shift <em>h</em> units to the left, replace <em>x</em> with <em>x</em> + <em>h</em>.
To shift <em>k</em> units up, add <em>k </em>to the end of the formula for the function.
To shift <em>k</em> units down, subtract <em>k</em> from the end of the formula.
Example:
is shifted <u>left</u> 2 units and <u>up</u> 6 units.
Caution: the right/left shifts sometimes look backwards!
Answer:
15/13
Step-by-step explanation:
Answer:
GCD(343,550) = 1
LCM(343,550) = 188650
GCD(89,110) = 1
LCM(89,110) = 9790
GCD(870,222) = 6
LCM(870,222) = 32190
Step-by-step explanation:
a) GCD(343,550)
343 - 550 | 1
...
There are no values for which both 343 and 550 are divisible by, so GCD(343,550)=1.
LCM(343,550)
343 - 550 | 2
343 - 275 | 5
343 - 55 | 5
343 - 11 | 7
49- 11 | 7
7 - 11 | 7
1 - 11 | 11
1 - 1
So LCM(343,550) = 2*5*5*7*7*7*11 = 188650
b) GCD(89,110)
Again, as in a), there are no values for which 89 and 110 are divisible by. So GCD(89,110) = 1.
LCM(89,110)
89 - 110 | 2
89 - 55 | 5
89 - 11 | 11
89 - 1 | 89
1 - 1
So LCM(89,110) = 2*5*11*89 = 9790
c) GCD(870,222)
870 - 222 | 2
435 - 111 | 3
145 - 37
There are no numbers for which 145 and 37 are both divisible by, so the algorithm ends there, and GCD(870,222) = 2*3 = 6
LCM(870,222)
870 - 222 | 2
435 - 111 | 3
145 - 37 | 5
29 - 37 | 29
1 - 37 | 37
1 - 1
So LCM(870,222) = 2*3*5*29*37 = 32190