Given problem is 
To simplify that we need to multiply and divide by conjugate of the denominator
conjugate of denominator 6+i will be 6-i as we just need to change sign of the imaginary part
Now multiply and divide by 6-i
Hence final answer is 
Answer:
4) y+2 = 3(x+1)
5) y+2 = -1(x-1)
6) y+3 = 0(x-2) OR y=3
Step-by-step explanation:
M is given and is the slope
X and Y change signs (positive becomes negative and vice versa)
Answer:
30sequences
Step-by-step explanation:
Using nx (n-1)
And
n is the number of ternary digits in the number.
So For 6 digits n is 6 so the number of numbers that have exactly one 1 AND exactly one 2 is 30.
That is 6(6-1)= 30
2(3)^3 + 4(3)^2-6(3)
2x 27 + 4x9 - 18
54 + 36 -18
= 72
