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defon
3 years ago
9

given the vector with a manitude of 9m at an angle a of -80 degrees, decompose this vector into two vector components oarallel t

o the x axis with a slope of
Mathematics
1 answer:
lana [24]3 years ago
3 0

Answer:

We have the magnitude, M, and the angle A.

(The angle is always measured from the +x-axis)

Then we have that:

x = M*cos(A)

y = M*sin(A)

in this case:

M = 9m

A = -80°

x = 9m*cos(-80°) = 1.562

y = 9m*sin(-80) = -8.86m

Now, the component parallel to the x axis is:

x = 9m*cos(-80°) = 1.562 m

And the slope of something parallel to the x-axis is always zero, as this is a constant line.

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3 years ago
3. Use the polynomial 12x^4 y^2 + 30x^3 y to answer the following questions?
barxatty [35]

Answer:

\huge\boxed{GCF:6x^3y}

\huge\boxed{Factored: 6x^3y(2x+5)}

Step-by-step explanation:

Look at both terms separately, and isolate each "part."

i.e. 12x^4y^2 becomes 12, x^4, y^2

So the problem becomes:

12, x^4, y^2 and

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Then, find the GCF of each term,

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Hope it helps :) and let me know if you want me to elaborate.

7 0
2 years ago
Prove that the max and min values of asinX + bcosX are respectively sqrt.(a^2+b^2) and -sqrt(a^2+b^2) .
strojnjashka [21]
The solution to the problem is as follows:
let y = asinx + bcosx 
<span>
dy/dx = acosx - bsinx </span>
<span>
= 0 for max/min </span>
<span>
bsinx = acosx </span>
<span>
sinx/cosx = a/b </span>
<span>
tanx = a/b </span>
<span>
then the hypotenuse of the corresponding right-angled triangle is √(a^2 + b^2) </span>

<span>the max/min of y occurs when tanx = a/b </span>
<span>
then sinx = a/√(a^2 + b^2) and cosx = b/√(a^2 + b^2) </span>
<span>
y = a( a/√(a^2 + b^2)) + b( b/√(a^2 + b^2)) </span>
<span>
= (a^2 + b^2)/√(a^2 + b^2) </span>
<span>
= √(a^2 + b^2)</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
6 0
3 years ago
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