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3 years ago

Select all equations that have graphs with the same y-intercept.

Mathematics

1 answer:

Firdavs [7]3 years ago

8 0

Y=3x-8,5x-8,2x-8,1/3x-8 how to find it is to look at the (x,y) if the equation have the same y (y-intercept)

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Helpppppppppppppppppppp

Sliva [168]

$a_1=11+(1-1)(4)=11+0=11\\\\a_2=11+(2-1)(4)=11+4=15$

so:

$a_2=a_1+\,?\\\\15=11+\,?\\\\\boxed{?=4}$

Answer B.

8 0

3 years ago

One cell phone plan charges $20 per month plus $.15 per minute used. A second cell phone plan charges $35 per month plus $.10 pe

SOVA2 [1]

20+0.15x = 35+0.10x

0.15x=15+0.10x

0.05x=15

x= 15/0.05

x= 300minutes

check:

300*.015 = 45+20=65

300*0.10 = 30 + 35 = 65

they equal

so number of minutes would be 300

7 0

3 years ago

Can someone please help me do this

Viefleur [7K]

Answer:

Step-by-step explanation:

CD is Pole

∠CAD = 4° {Alternate interior angles}

ΔCAD,

$\dfrac{opposite \ side}{adjacent \ side}= tan 4\\\\ \dfrac{90}{AD}=tan \ 4\\\\ \dfrac{90}{AD} = 0.069\\\\90 = 0.069*AD\\\\ \dfrac{90}{0.069}=AD\\\\AD = 1304 \ ft$

In ΔCDB,

∠B = 5° {Alternate interior angles}

$Tan \ 5 = \dfrac{90}{BD}\\\\0.09* BD = 90\\\\BD = \dfrac{90}{0.09}\\\\BD = 1000 \ ft$

4 0

3 years ago

What is the math problem answer?

azamat

To find the mid point add both X coordinates together and divide by 2 and then do the same with the y coordinates.

X coordinate: 4 + -6 = 4-6 = -2 / 2 = -1

Y coordinate: -2 + 3 = 1 / 2 = 1/2

Midpoint: ( -1, 1/2)

3 0

3 years ago

A ball is shot into the air using a brand new super-high-tech robotic arm to help baseball players practice catch fly balls.

stepladder [879]

Answer:

69 feet

Step-by-step explanation:

we have

$h(t)=-16t^{2}+64t+5$

where

h(t) is the height of the ball

t is the time in seconds

we know that the given equation is a vertical parabola open downward

The vertex is the maximum

the y-coordinate of the vertex represent the maximum height of the ball

Convert the quadratic equation into vertex form

The equation in vertex form is equal to

$y=(x-h)^{2}+k$

where

(h,k) is the vertex of the parabola

$h(t)=-16t^{2}+64t+5$

$h(t)-5=-16t^{2}+64t$

$h(t)-5=-16(t^{2}-4t)$

$h(t)-5-64=-16(t^{2}-4t+4)$

$h(t)-69=-16(t^{2}-4t+4)$

$h(t)-69=-16(t-2)^{2}$

$h(t)=-16(t-2)^{2}+69$

the vertex is the point (2,69)

therefore

The maximum height is 69 ft

6 0

3 years ago