Answer:
lgfksoi;knhoipjnzopbnzl;kn;lnogipuzhpoiupuoif
Explanation:
gfsk;nlkjnbahnguaok;nfhoaho;ah
The concentration of CH3OH in the solution is 2.18M
HOW TO CALCULATE MOLARITY:
- The molarity of a solution can be calculated by dividing the number of moles by its volume as follows:
- Molarity {M} = no. of moles (mol) ÷ volume (L)
- According to this question, 35.0 g of CH3OH (MM = 32.0 g/mol) are dissolved in 500.0 mL of solution. The number of moles of methanol is calculated as follows:
no. of moles = 35g ÷ 32g/mol
no. of moles = 1.09mol
- Molarity = no. of moles ÷ volume
Volume = 500mL = 0.500L
Molarity = 1.09mol ÷ 0.500L
Molarity = 2.18M
Therefore, the concentration of CH3OH in the solution is 2.18M
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<span>The answer is germline mutation. The main changes that matter to huge scale advancement are those that can be passed on to posterity. These happen in regenerative cells like eggs and sperm and are called germline mutation. A solitary germline transformation can have a scope of impacts: No change happens in phenotype.</span>
Answer:
The correct option is 3. "At pH 6.5 the enyzme is 50% active"
Explanation:
For the titratable group to be protonated and cause the enzyme to be in the active state, it needs to have gained a hydrogen cation (H+). In order for that to happen, there must be enough hydrogen cations in the environment of the enzyme, and hence, an acidic pH is required in this case.
Answer:
1/8
Explanation:
The following cross is done:
GGHhmm X GghhMm
If genes are unlinked they assort independently, and we can analyze one at a time to obtain the proportions in the offspring, and then multiply those probabilities to get the proportion of appearance of the GgHhmm genotype.
<u>Gene G/g</u>
P: GG x Gg
F1: 1/2 GG, 1/2 Gg
<u>Gene H/h</u>
P: Hh x hh
F1: 1/2 Hh, 1/2 hh
<u>Gene M/m</u>
P: mm x Mm
F1: 1/2 Mm, 1/2 mm
Total proportion of GgHhmm genotype = 1/2 x 1/2 x 1/2 = 1/8
