Answer:
3x + 2 < –7 or 3x + 2 > 7
The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
<h3>What is the least number of buses needed to carry 710 passengers? </h3>
Given that;
- Number of passengers n = 710
- Least number of buses need B = ?
To get the least number of buses, we say;
Number of buses B = 710 ÷ 150
Number of buses B = 4.7 ≈ 5
The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
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Answer:
96π
Step-by-step explanation:
V=96π
Answer:
13
Step-by-step explanation:
(12*2)/2+1 > 24/2+1 > 12+1 > 13
