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ehidna [41]
2 years ago
10

In the adjoining figure cross out dissimilar one and represent the set formed by following method​

Mathematics
1 answer:
Over [174]2 years ago
3 0

Answer:

cross out 4

Step-by-step explanation:

explanation

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What is the answer? pls help
worty [1.4K]

Answer:

117

Hope this helped :)

8 0
3 years ago
The straight line, Line L has an equation of 4x+y=7. Find the equation of the straight line perpendicular to Line L that passes
Jobisdone [24]

Answer:

Step-by-step explanation:

y = -4x + 7

perp. 1/4

y - 3 = 1/4(x + 8)

y - 3 = 1/4x + 2

y = 1/4x + 5

3 0
3 years ago
The perimeter of a rectangular piece of plastic is 30 millimeters. The area is 54 square millimeters. What are the dimensions of
Delvig [45]

Answer:

6 mm and 9 mm are the dimensions of the piece of plastic.

Step-by-step explanation:

Keep in mind the formulas for the area and perimeter of a rectangle:

A = lw

P = 2 (l + w)

List the factors of 54:

1, 2, 3, 6, 9, 18, 27, 54

POSSIBLE DIMENSIONS of the piece of plastic:

1 mm and 54 mm:

Area - 54 mm^2

Perimeter - 110 mm

2 mm and 27 mm

Area - 54 mm^2

Perimeter - 58 mm

3 mm and 18 mm

Area - 54 mm^2

Perimeter - 42 mm

6 mm and 9 mm

Area - 54 mm^2

Perimeter - 30 mm

The rectangular piece of plastic with the dimensions 6mm and 9 mm corresponds with the area and perimeter of the piece of plastic mentioned. So these are the correct dimensions.

Hope this helps!

6 0
3 years ago
What is the equation of this line?
chubhunter [2.5K]
It is a.) y = (3/2)x
4 0
3 years ago
Read 2 more answers
Length of a rectangle is 5 cm longer than the width. Four squares are constructed outside the rectangle such that each of the sq
stiv31 [10]

Answer:

18

Step-by-step explanation:

Remark

This is one of those questions that can throw you. The problem is that do you include the original rectangle or not. The way it is written it sounds like you shouldn't

However if you don't the question gives you 2 complex answers. (answers with the sqrt( - 1) in them.

Solution

Let the width = x

Let the length = x + 5

Area of the rectangle: L * w = x * (x + 5)

Area of the smaller squares (there are 2)

Area = 2*s^2

x = s

Area = 2 * x^2

Area of the larger squares = 2 * (x+5)^2

Total Area

x*(x + 5) + 2x^2 + 2(x + 5)^2 = 120                 Expand

x^2 + 5x + 2x^2 + 2(x^2 + 10x + 25) = 120     Remove the brackets

x^2 + 5x + 2x^2 + 2x^2 + 20x + 50 = 120      collect the like terms on the left

5x^2 + 25x +  50 = 120                                   Subtract 120 from both sides.

5x^2 + 25x - 70 = 0                                         Divide through by 5

x^2 + 5x - 14 = 0                                               Factor

(x + 7)(x - 2) = 0                                                 x + 7 has no meaning  

x - 2 =  0

x = 2                                                              

Perimeter

P = 2*w + 2*L

w = 2

L = 2 + 5

L = 7

P = 2*2 + 2 * 7

P = 4 + 14

P = 18

8 0
3 years ago
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