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3 years ago

Given the graph of a function below, Determine the interval in which the function has a negative value.

Mathematics

1 answer:

Serggg [28]3 years ago

8 0

Answer:

Step-by-step explanation:

The "value" of a function is the y-value.

Since we want negative y values, we look at "WHERE" the function is "UNDER" the y-axis.

Looking closely, it looks that function (the dip) is from x = -1 to x = 3

Hence, the function is negative at the interval -1 ≤ x ≤ 3

B is correct.

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Answer:

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2 years ago

What's the least common multiple of 6, 12 and 30

Licemer1 [7]

Answer:

the answer is 2

Step-by-step explanation:

2×4=6

2×6=12

2×15=30

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3 years ago

The Fish and Game Department stocked a lake with fish in the following proportions: 30% catfish, 15% bass, 40% bluegill, and 15%

vagabundo [1.1K]

Answer:

1) $\chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313$

2) $p_v =P(\chi^2_{3}>16.313)=0.000978$

And we got the same decision reject the null hypothesis at 5% of significance.

Step-by-step explanation:

Previous concepts

The Chi-Square test of independence is used "to determine if there is a significant relationship between two nominal (categorical) variables". And is defined with the following statistic:

$\chi^2 =\sum_{i=1}^n \frac{(O-E)^2}{E}$

Where O rpresent the observed values and E the expected values.

State the null and alternative hypothesis

Null hypothesis: The distribution is 30% catfish, 15% bass, 40% bluegill, and 15% pike

Alternative hypothesis: The distribution is NOT 30% catfish, 15% bass, 40% bluegill, and 15% pike

The observed values are given by the table given:

Catfish =112, BAss = 95, Bluegill=210, Pike=83

Calculate the expected values

In order to calculate the expected values we can use the following formula for each cell of the table

$E = \% Grand total$

$E_{Catfish}=500*0.3=150$

$E_{Bass}=500*0.15=75$

$E_{Bluegill}=500*0.4=200$

$E_{Pike}=500*0.15=75$

Part 1: Calculate the statistic

$\chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313$

$\chi^2 =16.313$

Calculate the critical value

First we need to calculate the degrees of freedom given by:

$df= (categories-1)=(4-1)= 3$

Since the confidence provided is 95% the significance would be $\alpha=1-0.95=0.05$ and we can find the critical value with the following excel code: "=CHISQ.INV(0.95,3)", and our critical value would be $\chi^2_{crit}=7.815$

We can calculate also the p value:

$p_v =P(\chi^2_{3}>16.313)=0.000978$

And we got the same decision reject the null hypothesis at 5% of significance.

5 0

3 years ago

What is the slope of the line whose equation is 5y + 6x - 2 = 0

koban [17]

All you need to do to find the slope here is put it into y = mx + b format.

5y + 6x - 2 = 0

the goal is to get the y alone, so...

5y = 2 - 6x

divide both sides by 5

y = 2/5 - (6/5)x

then, just to be clearer for y = mx + b ...... y = (-6/5)x + (2/5)

the slope should be (-6/5)

4 0

3 years ago

Read 2 more answers

How to solve (512) in a radical expression 1/3

katrin2010 [14]

<span> The exponent is negative so we factor out -1:
</span>

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3 years ago