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Rudiy27
4 years ago
7

Answer to this question

Mathematics
2 answers:
Roman55 [17]4 years ago
8 0
A, because the y intercept is positive 3, and slope is -1
seropon [69]4 years ago
4 0
The answer is A hope this helps
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Suppose that 2% of cereal boxes contain a prize and the other 98% contain the message, "sorry, try again." consider the random v
user100 [1]
<span>a) This is the sum of the probabilities of winning in 1, 2 or 3 boxes. 0.02 + (0.98*0.02) + (0.98*0.98*0.02) = 0.0588 b) Exactly three boxes requires the first two to lose. (0.98*0.98*0.02) = 0.0192 c) This is the complement of answer for a). 1-.0588 = .9412</span>
5 0
3 years ago
Which is the graph of f(x)=2(3)^x?
denis23 [38]

Answer:

Step-by-step explanation:

y = 2*3^x

x = 1

y = ?

y = 2*3^1

y =2 * 3

y = 6

The answer is the first graph.

6 0
3 years ago
Help with this question
larisa [96]

Answer:

-2

Step-by-step explanation:

2x + y = 10               Subtract 2x from both sides.

2x-2x + y = 10 - 2x  Combine the left.

y = 10 - 2x

The slope is the number in front of the x -- in this case - 2

The answer is - 2

4 0
3 years ago
PLEASE HELP ME PLEASE HELP ASAP THANKS (brainlest)
zloy xaker [14]

Answer:

0.999 units

Step-by-step explanation:

D=

\frac{3.14}{\pi}

D=0.9994930426

4 0
3 years ago
Read 2 more answers
Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5
givi [52]
<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]                            X=\left[\begin{array}{c}x\\y\end{array}\right]

and          B= \left[\begin{array}{c}11\\5\end{array}\right]

∴AX=B

adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]

A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6

∴A^{-1} =\frac{adj A}{|A|}

So,A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}

A^{-1} ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}

X =A^{-1}\times B

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c}  {6}\\  {11} \end{array}\right]}

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0
3 years ago
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