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Natali [406]
4 years ago
9

What does the variable represent in the equation 6-8p=38

Mathematics
2 answers:
saul85 [17]4 years ago
4 0

Answer:

-4

Step-by-step explanation:

GalinKa [24]4 years ago
3 0

Solving the equation  6-8p=38 we get value of p = -4

Step-by-step explanation:

We need to find the value of p in the equation 6-8p=38

Solving to find value of p:

6-8p=38\\Adding\,\,-6\,\,on\,\,both\,\,sides:\\6-8p-6=38-6\\-8p=32\\Divide\,\,both\,\,sides\,\,by\,\,-8\\\frac{-8p}{-8}=\frac{32}{-8}\\p=-4

So, solving the equation  6-8p=38 we get value of p = -4

Keywords: Solving Equations

Learn more about Solving Equations at:

  • brainly.com/question/1600376
  • brainly.com/question/1617787
  • brainly.com/question/9720317

#learnwithBrainly

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Answer:

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Step-by-step explanation:

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8 0
3 years ago
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jok3333 [9.3K]

Answer:

See explaination for answer! Hope this helps!

Step-by-step explanation:

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<u />

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3 years ago
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Oliga [24]
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7 0
3 years ago
Suppose a and b give the population of two states where a&gt;b . Compare the expressions and tell which of the given pair is gre
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4 0
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Read 2 more answers
Sketch the region enclosed by y=e3x,y=e5x and x=1. Decide whether to integrate with respect to x or y, and then find the area of
Lina20 [59]

The area of the region is \text { Area } \approx 23.12

Explanation:

The area of the region is given by

\text { Area }=\int_{0}^{1}\left(e^{5 x}-e^{3 x}\right) d x

Integrating the terms inside the bracket, we get,

\left[\frac{e^{5 x}}{5}-\frac{e^{3 x}}{3}\right]

Now, applying the limits for x for the integrated term,

Area=\frac{e^{5}}{5}-\frac{e^{3}}{3}-\frac{e^{0}}{5}+\frac{e^{0}}{3}

Any number to the power of zero is one. Thus, substituting the values, we get,

Area=\frac{e^{5}}{5}-\frac{e^{3}}{3}-\frac{1}{5}+\frac{1}{3}

Adding the like terms,

Area=\frac{e^{5}}{5}-\frac{e^{3}}{3}+\frac{2}{15}

Simplifying the terms, we get,

\text { Area } \approx 23.12

Thus, The area of the region is \text { Area } \approx 23.12

4 0
4 years ago
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