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Reika [66]
4 years ago
14

Estimate then add to find the combined length of the four highways shown in the table.is your answer resonable? Explain. Interst

ate 1-90 length 3,102 , 1-10 length 2,460, 1-70 lenght 2,153, 1-80 length 2,899
Mathematics
1 answer:
Olegator [25]4 years ago
7 0
To estimate, round 3102 to 3100
round 1-10 to 2500
1-70 to 2100 
1-80 to 2900
2900+2100+2500+3100=10600mi
Yes it is reasonable because you add and subtract numbers when estimating, however it is not exact
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Question is in the picture (surface area)
Marina CMI [18]

Answer:

Your answer is 62 square inches

Step-by-step explanation:

You can cross off 1 & 2, as they are too small.

Lets split this up.

(2*3)+(2*3)+(3*5)+(3*5)+(2*5)+(2*5)

2*3 + 2*3 = 12

3*5 + 3*5 = 30

2*5 + 2*5 = 20

30+20+12 = 62

7 0
2 years ago
9. What is the formula to find the sum of the interior angles for any polygon?
SOVA2 [1]

polygon: (n-2) × 180

n: nonagon

octagon has 8 sides

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4 years ago
A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the
Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= \pi r^2h

According to the problem,

\pi r^2 h=25

\Rightarrow h=\frac{25}{\pi r^2}

The surface area of the base of the can is = \pi r^2

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× \pi r^2)

The lateral surface area of the can is = 2\pi rh

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× 2\pi rh)

                                                 =\$2.5 \pi r h

Total cost of metal is C= 2.00 \pi r^2+2.5 \pi r h

Putting h=\frac{25}{\pi r^2}

\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}

\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}

Differentiating with respect to r

C'=4\pi r- \frac{62.5}{ r^2}

Again differentiating with respect to r

C''=4\pi + \frac{125}{ r^3}

To find the minimize cost, we set C'=0

4\pi r- \frac{62.5}{ r^2}=0

\Rightarrow 4\pi r=\frac{62.5}{ r^2}

\Rightarrow  r^3=\frac{62.5}{ 4\pi}

⇒r=1.71

Now,

\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0

When r=1.71 cm, the metal cost will be minimum.

Therefore,

h=\frac{25}{\pi\times 1.71^2}

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

6 0
3 years ago
Ali spends 30% monthly income on food articles, 40% of the remaining on conveyance and clothes and saves 50% of the remaining. I
Romashka [77]

Ali saves Rs 2576 every month

Step-by-step explanation:

  • Step 1: Given Ali's monthly salary = Rs 18400. Calculate the amount spent on food articles

Amount spent on food = 30% of 18400 = 30/100 × 18400 = Rs 5520

  • Step 2: Find the remaining amount.

Remaining amount = 18400 - 5520 = Rs 12880

  • Step 3: Find amount spend on conveyance and clothes

Amount spent on conveyance and clothes = 40% of 12880

                              = 40/100 × 12880 = Rs 5152

  • Step 4: Find his monthly savings.

Monthly savings = 50% of 5152 = 50/100 × 5152 = Rs 2576

5 0
4 years ago
Read 2 more answers
Simplify to create an equivalent expression.
Olin [163]
<span>−y−3(−3y+5)
= </span><span>−y + 9y - 15
= 8y - 15

answer
</span><span>d.8y-15</span>
8 0
3 years ago
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