Answer: Option C. Married and grade 2 (92.6%) is higher than Single and grade 2 (5.2%)
Solution:
Conditional relative frequency single employees in grade 2:
[(Single employees in job grade 2)/(Total employees in job grade 2)]*100%=
(222/4,239)*100%=0.052370842*100%=5.2370842% approximately 5.2%
Conditional relative frequency married employees in grade 2:
[(Married employees in job grade 2)/(Total employees in job grade 2)]*100%=
(3,927/4,239)*100%=0.926397735*100%=92.6397735% approximately 92.6%
92.6%>5.2%:
Married and grade 2 (92.6%) is higher than Single and grade 2 (5.2%)
Answer:
a) 0.7734
Step-by-step explanation:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

(a) what proportion of children aged 13 to 15 years old have scores on this test above 83 ?
This is 1 subtracted by the pvalue of Z when X = 83. So



has a pvalue of 0.2266
1 - 0.2266 = 0.7734
The answer is 0.7734
We can use the Pythagorean theorem:
c² = a² + b²
In this case:
6² = 3² + 4²
36 = 9 + 16
36 = 25 ( not correct )
This is not a right triangle.
Answer:
B ) The triangle in question is not a right triangle.
Answer:
43.1
Step-by-step explanation:
Look at the picture! Double check my work but I am pretty sure I did it correctly.
Answer:
Bro resend you question I think it is not written correct. Hope you understand me